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The 27-qubit Counterexample to the LU-LC Conjecture is Minimal

Nathan Claudet

Abstract

It was once conjectured that two graph states are local unitary (LU) equivalent if and only if they are local Clifford (LC) equivalent. This so-called LU-LC conjecture was disproved in 2007, as a pair of 27-qubit graph states that are LU-equivalent, but not LC-equivalent, was discovered. We prove that this counterexample to the LU-LC conjecture is minimal. In other words, for graph states on up to 26 qubits, the notions of LU-equivalence and LC-equivalence coincide. This result is obtained by studying the structure of 2-local complementation, a special case of the recently introduced r-local complementation, and a generalization of the well-known local complementation. We make use of a connection with triorthogonal codes and Reed-Muller codes.

The 27-qubit Counterexample to the LU-LC Conjecture is Minimal

Abstract

It was once conjectured that two graph states are local unitary (LU) equivalent if and only if they are local Clifford (LC) equivalent. This so-called LU-LC conjecture was disproved in 2007, as a pair of 27-qubit graph states that are LU-equivalent, but not LC-equivalent, was discovered. We prove that this counterexample to the LU-LC conjecture is minimal. In other words, for graph states on up to 26 qubits, the notions of LU-equivalence and LC-equivalence coincide. This result is obtained by studying the structure of 2-local complementation, a special case of the recently introduced r-local complementation, and a generalization of the well-known local complementation. We make use of a connection with triorthogonal codes and Reed-Muller codes.

Paper Structure

This paper contains 9 sections, 15 theorems, 9 equations, 4 figures.

Key Result

Theorem 1

LU=LC holds for graph states on up to 26 qubits.

Figures (4)

  • Figure 1: A 27-qubit counterexample to the LU-LC conjecture Ji07Tsimakuridze17, that is, a pair of graph states that are LU-equivalent but not LC-equivalent. The graphs have 6 bottom vertices. There is one top vertex of degree 5 per set of 5 bottom vertices, and one top vertex of degree 4 per set of 4 bottom vertices; leading to $\binom{6}{5} + \binom{6}{4} = 21$ top vertices. In the leftmost graph, the bottom vertices form an independent set, while in the rightmost graph, the bottom vertices are fully connected. Applying $X(\pi/4)$ on the top qubits and $Z(\pi/4)$ on the bottom qubits maps one graph state to the other. Proving that these two graph states are not LC-equivalent is more involved, a proof can be found in Tsimakuridze17.
  • Figure 2: A 28-qubit counterexample to the LU-LC conjecture Tsimakuridze17, that is, a pair of graph states that are LU-equivalent but not LC-equivalent. The graphs have 7 bottom vertices. The top vertices are all of degree 5, and there is one top vertex per set of 5 bottom vertices, leading to $\binom{7}{5} = 21$ top vertices. In the leftmost graph, the bottom vertices form an independent set, while in the rightmost graph, the bottom vertices are fully connected. Applying $X(\pi/4)$ on the top qubits and $Z(\pi/4)$ on the bottom qubits maps one graph state to the other. Proving that these two graph states are not LC-equivalent is more involved, a proof can be found in Tsimakuridze17, and a proof in the formalism of $r$-local complementation can be found in claudet2024local. The 27-qubit counterexample to the LU-LC conjecture (see Figure \ref{['fig:ce27']}) can be recovered by removing one bottom vertex.
  • Figure 3: One of the 16-vertex bipartite graphs corresponding to the unique unital triorthogonal subspace in $\mathbb F^{16}_2$, from which the original magic state distillation code by Bravyi and Kitaev Bravyi2005 and the first code of the Bravyi-Haah family Bravyi2012 can be derived nezami2022. We name the bottom vertices 1, 2, 3, 4 and 5, and we name the top vertices after their neighborhood. One of the top vertices is adjacent to every bottom vertex: $\{1,2,3,4,5\}$. The $\binom{5}{3} = 10$ other top vertices are all possible vertices of degree 3: $\{1,2,3\}$, $\{1,2,4\}$, $\{1,2,5\}$, $\{1,3,4\}$, $\{1,3,5\}$, $\{1,4,5\}$, $\{2,3,4\}$, $\{2,3,5\}$, $\{2,4,5\}$ and $\{3,4,5\}$. The set of top vertices is 2-incident. A 2-local complementation on the top vertices leaves the graph invariant, i.e. does not create or remove any edge. Thus, no counterexample to the LU-LC conjecture can be derived from this graph.
  • Figure 4: The leftmost graph is one of the 24-vertex bipartite graphs corresponding to the unique unital triorthogonal subspace in $\mathbb F^{24}_2$, from which the second code of the Bravyi-Haah family Bravyi2012 can be derived nezami2022. We name the bottom vertices 1, 2, 3, 4, 5, 6 and 7, and we name the top vertices after their neighborhood. One of the top vertices is adjacent to every bottom vertex: $\{1,2,3,4,5,6,7\}$. 3 top vertices are of degree 5: $\{1,2,3,4,5\}$, $\{1,2,3,4,6\}$ and $\{1,2,3,4,7\}$. The $\binom{3}{2}\times\binom{4}{1} + \binom{3}{3} = 3 \times 4 +1 = 11$ other top vertices are of degree 3, they are all possible vertices of degree 3 with 2 or more neighbors among the vertices 4, 5 and 6: $\{1,5,6\}$, $\{2,5,6\}$, $\{3,5,6\}$, $\{4,5,6\}$, $\{1,5,7\}$, $\{2,5,7\}$, $\{3,5,7\}$, $\{4,5,7\}$, $\{1,6,7\}$, $\{2,6,7\}$, $\{3,6,7\}$, $\{4,6,7\}$ and $\{5,6,7\}$. The set of top vertices is 2-incident. A 2-local complementation on the top vertices maps the leftmost graph to the rightmost graph by creating 3 edges: one between 5 and 6, one between 5 and 7, and one between 6 and 7. This transformation can also be obtained with a single local complementation on the vertex $\{5,6,7\}$. Thus, no counterexample to the LU-LC conjecture can be derived from these graphs.

Theorems & Definitions (27)

  • Theorem 1
  • Corollary 1
  • Definition 1: claudet2024local
  • Definition 2: claudet2024local
  • Example 1
  • Proposition 1: claudet2024local
  • Proposition 2: claudet2025deciding
  • Lemma 1
  • Example 2
  • Lemma 2
  • ...and 17 more