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Orbits of the three-body problem with large potential

Richard Moeckel

Abstract

Consider the planar three-body problem with masses positive $m_1,m_2,m_3$ position vector $q(t) = (q_1(t),q_2(t),q_3(t))\in\mathbb{R}^6$. Let $$U(q) = \frac{m_1m_2}{r_{12}}+\frac{m_1m_3}{r_{13}}+\frac{m_2m_3}{r_{23}}$$ where $r_{ij}=|q_i-q_j|$. Assume that the angular momentum is nonzero so that triple collision is impossible and fix any negative energy.. Then given any constant $K>0$ there are solutions with $U(q(t))\ge K$ for all $t\in\mathbb{R}$. These solutions will have a single close approach to triple collision. The configuration will always be a tight binary with $m_1, m_2$ close and the distance from the binary to $m_3$ diverging as $t\rightarrow\pm\infty$.

Orbits of the three-body problem with large potential

Abstract

Consider the planar three-body problem with masses positive position vector . Let where . Assume that the angular momentum is nonzero so that triple collision is impossible and fix any negative energy.. Then given any constant there are solutions with for all . These solutions will have a single close approach to triple collision. The configuration will always be a tight binary with close and the distance from the binary to diverging as .
Paper Structure (2 sections, 3 theorems, 40 equations)

This paper contains 2 sections, 3 theorems, 40 equations.

Key Result

Theorem 1

Given any constant $K>0$ there are solutions of the negative-energy, planar three-body problem with $U(q(t))\ge K$ for all $t\in\mathbb{R}$.

Theorems & Definitions (6)

  • Theorem 1
  • Lemma 1
  • proof
  • Lemma 2
  • proof
  • proof : Proof of Theorem \ref{['th_UK']}