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On the Generalized Honeymoon Oberwolfach Problem

Masoomeh Akbari

Abstract

The generalized Honeymoon Oberwolfach Problem (HOP) asks whether it is possible to seat $2n$ participants consisting of $n$ newlywed couples at a conference with $s$ tables of size $2$ and $t$ ''round'' tables of sizes $2m_1, 2m_2, \ldots, 2m_t$, where $n = s + \sum_{i=1}^{t} m_i $ with all $m_i \geq 2$, over several nights so that each participant sits next to their spouse every time and next to each other participant exactly once. We denote this problem by $\mathrm{HOP}(2^{\langle s \rangle}, 2m_1, \ldots, 2m_t)$. This paper is the first of two papers investigating the generalized HOP. While the second paper will deal with the generalized HOP with a single round table (i.e. table of size at least $4$), the present work develops solutions for the generalized HOP with multiple round tables. In particular, we present solutions to certain cases with two round tables, showing that a solution to $\mathrm{HOP}(2^{\langle s \rangle}, 2m_1, 2m_2)$ exists when $n \equiv 1 \pmod{(2m_1 + 2m_2)}$ or $n \equiv m_1 + m_2 \pmod{(2m_1 + 2m_2)}$. We also develop solutions for cases with small round tables, showing that $\mathrm{HOP}(2^{\langle s \rangle}, 2m_1, \dots, 2m_t)$ has a solution whenever $m = m_1 + \dots + m_t \leq 10$, $n = s + m$ is odd, and $n(n - 1) \equiv 0 \pmod{2m}$.

On the Generalized Honeymoon Oberwolfach Problem

Abstract

The generalized Honeymoon Oberwolfach Problem (HOP) asks whether it is possible to seat participants consisting of newlywed couples at a conference with tables of size and ''round'' tables of sizes , where with all , over several nights so that each participant sits next to their spouse every time and next to each other participant exactly once. We denote this problem by . This paper is the first of two papers investigating the generalized HOP. While the second paper will deal with the generalized HOP with a single round table (i.e. table of size at least ), the present work develops solutions for the generalized HOP with multiple round tables. In particular, we present solutions to certain cases with two round tables, showing that a solution to exists when or . We also develop solutions for cases with small round tables, showing that has a solution whenever , is odd, and .
Paper Structure (15 sections, 36 theorems, 69 equations, 5 figures, 2 tables)

This paper contains 15 sections, 36 theorems, 69 equations, 5 figures, 2 tables.

Key Result

Theorem 1.1

Let $s, m_1, m_2$ be integers such that $s \geq 0$ and $2 \leq m_1 \leq m_2$. Let $m = m_1 + m_2$ and $n = s + m$. Then HOP$(2^{\langle s \rangle}, 2m_1, 2m_2)$ has a solution in each of the following cases:

Figures (5)

  • Figure 1: The $F_i$ subgraph in Lemma \ref{['lem:Newtool-1b']} for $m\equiv 2\ ({\rm mod}\ 4)$.
  • Figure 2: Subgraph $F_i$ in Lemma \ref{['lem:Newtool-T2']} for $m\equiv 1\ ({\rm mod}\ 4)$ and $m\geq 9$.
  • Figure 3: $(C_3, C_3)$-subgraphs of $4K_{9}^{\bullet}$ that generate an HOP $(C_3,C_3)$-decomposition for $4K_{9}^{\bullet}$.
  • Figure 4: $(C_2, C_4, C_4)$-subgraphs of $2K_{25}^{\circ}$ that generate an HOP $(C_2, C_4, C_4)$-decomposition of $4K_{25}^{\bullet}$.
  • Figure 5: $(C_2, C_3, C_5)$-subgraphs of $4K_{25}^{\bullet}$ that generate an HOP $(C_2, C_3, C_5)$-decomposition of $4K_{25}^{\bullet}$.

Theorems & Definitions (38)

  • Theorem 1.1
  • Theorem 1.2
  • Definition 3.1
  • Definition 3.2
  • Theorem 3.3
  • Lemma 3.4
  • Lemma 3.5
  • Lemma 3.6
  • Lemma 3.7
  • Theorem 3.8
  • ...and 28 more