A 910-block explicit construction guaranteeing a triple intersection with every $6$-subset of $[60]$
Paulo Henrique Cunha Gomes
TL;DR
This work presents an explicit construction of a 910-block family of 6-subsets on $[60]$ with the triple-intersection property, i.e., every 6-subset $S$ intersects some block in at least three elements, equivalently a radius-$3$ covering of the Johnson graph $J(60,6)$. The construction uses a simple two-halves split, internal pairings, and unions of three pairs to form blocks, yielding a concrete upper bound of $910$ for the covering number. A crude counting argument shows a general lower bound of $97$ blocks, and the paper discusses a generalization to $[2m]$ with $m$ even, along with an exploration of potential partition schemes and their limitations. Together with an analysis of limitations of certain splits and an alternative $(5,5)$ partition approach, the results illuminate explicit strategies for covering designs in Johnson graphs and provide a transparent benchmark for related combinatorial constructions and coding-theoretic contexts.
Abstract
We present a simple explicit family $\mathcal{B}$ of $910$ $6$-subsets of $[60]=\{1,\dots,60\}$ such that every $6$-subset $S\subset[60]$ intersects at least one block $B\in\mathcal{B}$ in at least three elements, i.e.\ $|S\cap B|\ge 3$. Equivalently, $\mathcal{B}$ is a covering (dominating set) of the Johnson graph $J(60,6)$ with covering radius $3$ in the Johnson metric. The construction is purely combinatorial, based on a fixed split of $[60]$ into two halves, a pairing of each half, and a pigeonhole argument. We also record a crude counting lower bound and a straightforward generalization to $[2m]$ (with $m$ even).
