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On cyclically covering subspaces of $\mathbb{F}^n_q$

Yangcheng Li, Pingzhi Yuan, Shuang Li, Yuanpeng Zeng

TL;DR

The paper studies cyclically covering subspaces of $\mathbb{F}_q^n$ by characterizing when $h_q(n)=0$ using an isomorphism-based framework that links $\mathbb{F}_q^n$, $\mathbb{F}_{q^n}$, and $\mathbb{F}_q[x]/(x^n-1)$. It derives equivalent conditions via invariant subspaces, trace-orthogonal constructions, and direct-sum decompositions, and applies these to obtain zero-codimension results such as $h_q(\ell^t)=0$ when $q$ is a primitive root modulo $\ell^t$, as well as a doubling property $h_q(2n)=0$ for odd $n$ when $h_q(n)=0$. Additionally, the work connects coverings in $\mathbb{F}_{q^m}^n$ to those in $\mathbb{F}_q^{mn}$, yielding transfer criteria and bounds, and provides concrete examples (e.g., $h_3(11)=h_3(16)=1$) along with sufficient conditions for $h_{q^m}(n)=0$ in various arithmetic settings, including $h_4(n)=0$ for $n=3$ or $n=2^d$. Overall, the results broaden the toolkit for understanding cyclic coverings and give practical criteria for zero codimension across different finite-field regimes.

Abstract

For a prime power \( q \) and a positive integer \( n \), a subspace \( U \subseteq \mathbb{F}_q^n \) is called cyclically covering if the union of all its cyclic shifts covers the whole space \( \mathbb{F}_q^n \). Let \( h_q(n) \) denote the maximum possible codimension of such a subspace. This paper focuses on the case \( h_q(n) = 0 \). We provide necessary and sufficient conditions under which \( h_q(n) = 0 \) holds. As an application, we show that \( h_q(\ell^t) = 0 \) whenever \( q \) is a primitive root modulo \( \ell^t \). Moreover, we prove that if \( n \) is odd and \( h_q(n) = 0 \), then also \( h_q(2n) = 0 \). As an example, we show that \( h_3(11) =h_3(16) = 1 \). Furthermore, we investigate the relationship between the coverings of \(\mathbb{F}_{q^m}^n\) and \(\mathbb{F}_q^{mn}\), and obtain several sufficient conditions for \(h_{q^m}(n) = 0\). Specifically, we derive that if \(n = 3\) or \(n = 2^d\) (where \(d\) is a nonnegative integer), then \(h_4(n) = 0\).

On cyclically covering subspaces of $\mathbb{F}^n_q$

TL;DR

The paper studies cyclically covering subspaces of by characterizing when using an isomorphism-based framework that links , , and . It derives equivalent conditions via invariant subspaces, trace-orthogonal constructions, and direct-sum decompositions, and applies these to obtain zero-codimension results such as when is a primitive root modulo , as well as a doubling property for odd when . Additionally, the work connects coverings in to those in , yielding transfer criteria and bounds, and provides concrete examples (e.g., ) along with sufficient conditions for in various arithmetic settings, including for or . Overall, the results broaden the toolkit for understanding cyclic coverings and give practical criteria for zero codimension across different finite-field regimes.

Abstract

For a prime power and a positive integer , a subspace is called cyclically covering if the union of all its cyclic shifts covers the whole space . Let \( h_q(n) \) denote the maximum possible codimension of such a subspace. This paper focuses on the case \( h_q(n) = 0 \). We provide necessary and sufficient conditions under which \( h_q(n) = 0 \) holds. As an application, we show that \( h_q(\ell^t) = 0 \) whenever is a primitive root modulo . Moreover, we prove that if is odd and \( h_q(n) = 0 \), then also \( h_q(2n) = 0 \). As an example, we show that \( h_3(11) =h_3(16) = 1 \). Furthermore, we investigate the relationship between the coverings of and , and obtain several sufficient conditions for \(h_{q^m}(n) = 0\). Specifically, we derive that if or (where is a nonnegative integer), then \(h_4(n) = 0\).
Paper Structure (6 sections, 19 theorems, 78 equations, 1 table)

This paper contains 6 sections, 19 theorems, 78 equations, 1 table.

Key Result

Lemma 1.1

Cameron-Ellis-Raynaud Let $q$ be a power of prime $p$, and $n,m,d,k \in \mathbb{N}$, then the following hold. $(\mathrm{i})$$h_2(n) \geq 2$, $n > 3$. $(\mathrm{ii})$$h_q(nm) \geq \max\{h_q(n), h_q(m)\}.$$(\mathrm{iii})$$h_q(n) \leq \lfloor\log_q(n)\rfloor$. $(\mathrm{iv})$$h_q(q^d - 1) = d - 1 = \lf

Theorems & Definitions (39)

  • Lemma 1.1
  • Lemma 1.2
  • Lemma 1.3
  • Lemma 1.4
  • Theorem 3.1
  • proof
  • Remark 3.1
  • Theorem 3.2
  • proof
  • Theorem 3.3
  • ...and 29 more