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Stationary phase with Cauchy singularity. A critical point of signature $(+,-)$

Christian Klein, Johannes Sjöstrand, Maher Zerzeri

TL;DR

The paper develops a rigorous small-$h$ asymptotic framework for a solid Cauchy transform with a Cauchy-type singularity near a stationary point of oscillatory phase. When the pole lies close to a stationary point, a polarization method in $\mathbb{C}^2$ combined with Stokes' theorem yields a three-term decomposition of the integral, with the leading terms described by Dawson-type special functions and explicit $h^{1/2}$-scaling factors. The first term $I(\zeta,1)$ is analyzed via a 1D stationary-phase reduction on a Cartesian contour, the second term $II(\zeta,1)$ via an auxiliary $t$-integral representation with detailed intermediate and small-$\varepsilon$ regime analysis, and the third term $III(\zeta,1)$ is shown to be $O(h^{\infty})$. Collectively, the results provide concrete, rotation-invariant leading-order expressions for the integral across regimes $0<|\zeta|<h^{1/2+\delta}$ and offer insight into d-bar problems in 2D integrable systems and related inverse problems. The approach highlights the utility of complex contour deformations, polarization, and special-function representations in high-frequency asymptotics.

Abstract

Asymptotic expressions for an integral appearing in the solution of a d-bar problem are presented. The integral is a solid Cauchy transform of a function with a rapidly oscillating phase with a small parameter $h$, $0<h\ll 1$. Whereas standard steepest descent approaches can be applied to the case where the stationary points of the phase $ω_{k}$, $k=1,\ldots, N$ are far from the singularity $ζ$ of the integrand, a polarization approach is proposed for the case that $|ζ-ω_{k}|<\mathcal{O}(\sqrt{h})$ for some $k$. In this case the problem is studied in $\mathbb{C}^{2}$ ($\tildeω:=\barω$ is treated as an independent variable) on steepest descent contours. An application of Stokes' theorem allows for a decomposition of the integral into three terms for which asymptotics expressions in terms of special functions are given.

Stationary phase with Cauchy singularity. A critical point of signature $(+,-)$

TL;DR

The paper develops a rigorous small- asymptotic framework for a solid Cauchy transform with a Cauchy-type singularity near a stationary point of oscillatory phase. When the pole lies close to a stationary point, a polarization method in combined with Stokes' theorem yields a three-term decomposition of the integral, with the leading terms described by Dawson-type special functions and explicit -scaling factors. The first term is analyzed via a 1D stationary-phase reduction on a Cartesian contour, the second term via an auxiliary -integral representation with detailed intermediate and small- regime analysis, and the third term is shown to be . Collectively, the results provide concrete, rotation-invariant leading-order expressions for the integral across regimes and offer insight into d-bar problems in 2D integrable systems and related inverse problems. The approach highlights the utility of complex contour deformations, polarization, and special-function representations in high-frequency asymptotics.

Abstract

Asymptotic expressions for an integral appearing in the solution of a d-bar problem are presented. The integral is a solid Cauchy transform of a function with a rapidly oscillating phase with a small parameter , . Whereas standard steepest descent approaches can be applied to the case where the stationary points of the phase , are far from the singularity of the integrand, a polarization approach is proposed for the case that for some . In this case the problem is studied in ( is treated as an independent variable) on steepest descent contours. An application of Stokes' theorem allows for a decomposition of the integral into three terms for which asymptotics expressions in terms of special functions are given.
Paper Structure (15 sections, 17 theorems, 595 equations)

This paper contains 15 sections, 17 theorems, 595 equations.

Key Result

Proposition 1.1

Under the above assumptions the integrals $\mathrm{I}(\zeta ,1)$, $\mathrm{II}(\zeta ,1)$, $\mathrm{III}(\zeta ,1)$ are well defined and respectively equal to $\underset{\delta \to 0}{\lim}\, \mathrm{I}(\zeta ,1-\delta )$, $\underset{\delta \to 0}{\lim} \, \mathrm{II}(\zeta ,1-\delta )$, $\underset{

Theorems & Definitions (23)

  • Proposition 1.1
  • Theorem 1.2
  • Remark 1.3
  • Proposition 2.1
  • Lemma 3.1
  • Remark 3.2
  • Remark 3.3
  • Lemma 3.4
  • Proposition 3.5
  • Lemma 4.1
  • ...and 13 more