Nash approximation of differentiable semialgebraic maps
Antonio Carbone, José F. Fernando
TL;DR
This work establishes that Nash manifolds with corners are $({\mathcal N},\mu)$-${\tt ats}$ for all $\mu\ge0$, meaning every ${\mathcal S}^{\mu}$-map from a locally compact semialgebraic set to such a target can be approximated by Nash maps in the strong Whitney topology. The authors develop a robust toolkit—including pushing corners inside interiors with controlled derivatives, relative Nash approximation, and a trimmed Whitney topology—to prove universal approximation and to derive Nash homotopies from semialgebraic homotopies. These results bridge semialgebraic and Nash categories for manifold-with-corners targets, with direct applications to Nash homotopy theory and potential extensions to broader tame settings. The approach leverages pushing/diffeomorphism constructions, Nash envelopes, and compatibility with ${\mathcal S}^{\mu}$-topologies, providing a flexible framework for approximating differentiable semialgebraic maps by Nash maps in intricate geometric contexts.
Abstract
Let $T\subset{\mathbb R}^n$ be a semialgebraic set and let $μ\ge0$ be a non-negative integer. We say that $T$ is a {\em Nash $μ$-approximation target space} (or a $({\mathcal N},μ)$-${\tt ats}$ for short) if it has the following universal approximation property: {\em For each $m\in{\mathbb N}$ and each locally compact semialgebraic subset $S\subset{\mathbb R}^m$, the subspace of Nash maps ${\mathcal N}(S,T)$ is dense in the space ${\mathcal S}^μ(S,T)$ of ${\mathcal C}^μ$ semialgebraic maps between $S$ and $T$}. A necessary condition to be a $({\mathcal N},μ)$-${\tt ats}$ is that $T$ is locally connected by analytic paths. In this paper we show: {\em Nash manifolds with corners are $({\mathcal N},μ)$-${\tt ats}$ for each $μ\geq0$}. As an application of a stronger version of the previous statement, we show that if two Nash maps $f,g:S\to Q$, where $S$ is a locally compact semialgebraic set of ${\mathbb R}^m$ and $Q$ is a Nash manifold with corners, are close enough in the (strong) Whitney's semialgebraic topology of ${\mathcal S}^0(S,T)$ (and consequently they are (continuous) semialgebraically homotopic), then $f,g$ are Nash homotopic.
