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Some New Results on Sequence Reconstruction Problem for Deletion Channels

Xiang Wang, Weijun Fang, Han Li, Fang-Wei Fu

TL;DR

This paper studies the sequence reconstruction problem over binary deletion channels by analyzing $N(n,d,t)$, the maximum intersection of two deletion balls of radius $t$ for sequences at Levenshtein distance at least $d$. It first derives a concrete lower bound $N(n,3,t)\geq M(n,t)$ for all $n\geq 13$ and $t\geq 4$, where $M(n,t)$ is a linear combination of deletion-ball counts $D(\cdot,\cdot)$; notably, for $t=4$ this bound is tight, yielding $N(n,3,4)=20n-166$ for all $n\geq 13$, achieved by explicit constructions with $d_L(\mathbf{x},\mathbf{y})\ge 3$. The upper bound argument shows $|D_4(\mathbf{x})\cap D_4(\mathbf{y})|\le 20n-166$ for all $n\ge 13$ and $d_L(\mathbf{x},\mathbf{y})\ge 3$, verified for the base cases $n=13,14$ by computer and completed by an induction over structured subcases (a)–(f) aided by several technical lemmas. Together, these results establish the exact value $N(n,3,4)=20n-166$ for all $n\ge 13$ and outline a general conjecture for $t\ge 5$ that the same $M(n,t)$ governs $N(n,3,t)$ asymptotically, with small-$n$ instances also cataloged. The work advances understanding of deletion-channel reconstruction bounds and informs design of deletion-correcting constructs in binary sequences.

Abstract

Levenshtein first introduced the sequence reconstruction problem in $2001$. In the realm of combinatorics, the sequence reconstruction problem is equivalent to determining the value of $N(n,d,t)$, which represents the maximum size of the intersection of two metric balls of radius $t$, given that the distance between their centers is at least $d$ and the sequence length is $n$. In this paper, We present a lower bound on $N(n,3,t)$ for $n\geq 13$ and $t \geq 4$. For $t=4$, we prove that this lower bound is tight. This settles an open question posed by Pham, Goyal, and Kiah, confirming that $N(n,3,4)=20n-166$ for all $n \geq 13$.

Some New Results on Sequence Reconstruction Problem for Deletion Channels

TL;DR

This paper studies the sequence reconstruction problem over binary deletion channels by analyzing , the maximum intersection of two deletion balls of radius for sequences at Levenshtein distance at least . It first derives a concrete lower bound for all and , where is a linear combination of deletion-ball counts ; notably, for this bound is tight, yielding for all , achieved by explicit constructions with . The upper bound argument shows for all and , verified for the base cases by computer and completed by an induction over structured subcases (a)–(f) aided by several technical lemmas. Together, these results establish the exact value for all and outline a general conjecture for that the same governs asymptotically, with small- instances also cataloged. The work advances understanding of deletion-channel reconstruction bounds and informs design of deletion-correcting constructs in binary sequences.

Abstract

Levenshtein first introduced the sequence reconstruction problem in . In the realm of combinatorics, the sequence reconstruction problem is equivalent to determining the value of , which represents the maximum size of the intersection of two metric balls of radius , given that the distance between their centers is at least and the sequence length is . In this paper, We present a lower bound on for and . For , we prove that this lower bound is tight. This settles an open question posed by Pham, Goyal, and Kiah, confirming that for all .
Paper Structure (15 sections, 26 theorems, 180 equations, 1 figure)

This paper contains 15 sections, 26 theorems, 180 equations, 1 figure.

Key Result

Theorem 2

For $1 \leq t < n$, Furthermore, when $\mathbf{x}=\mathbf{a}_n$ and $\mathbf{y}$ is either $0\,1\,\mathbf{a}_{n-2}$ or $0\,\mathbf{a}_{n-1}$, we have $d_L(\mathbf{x},\mathbf{y})=1$ and $|D_t(\mathbf{x})\cap D_t(\mathbf{y})|=N(n,1,t)$.

Figures (1)

  • Figure 1: Outline of proof of upper bound.

Theorems & Definitions (45)

  • Definition 1
  • Theorem 2: Levenshtein L1
  • Theorem 3: Gabrys and Yaakobi Gabrys)
  • Corollary 4
  • Theorem 5: Pham, Goyal, and Kiah Pham2)
  • Remark 1
  • Theorem 6
  • Proposition 7: Gabrys
  • Proposition 8: Gabrys
  • Lemma 9
  • ...and 35 more