Genus two embedded minimal surfaces in $\mathbb{S}^3$ with bidihedral symmetry
José M. Espinar, Joaquín Pérez
TL;DR
The paper proves that the Lawson genus-2 embedded minimal surface $\xi_{2,1}$ is the unique closed embedded minimal surface of genus $2$ in $\mathbb{S}^3$ whose isometry group contains the bidihedral group $D_{4h}$. The authors develop a two-stage strategy: (i) analyze a fundamental piece under $D_{4h}$ symmetry and its conjugate boundary, recoding the problem as a Plateau problem for geodesic right-angled pentagons, and (ii) solve a closing problem by balancing the length of a reflective geodesic $\gamma$ and an angle function $\Theta$ so that Schwarz reflections yield a complete, embedded, $D_{4h}$-symmetric surface. A detailed study of a two-parameter family of geodesic pentagons $\mathcal P_{l,\omega}$ (and a one-parameter family $\mathcal P_{\sigma}$) yields minimal disks $\Sigma_{l,\omega}$ and their conjugates $\Sigma^*_{l,\omega}$; the closing problem reduces to finding a unique $(l,\omega)$ with $L(l,\omega)=\pi/2$ and $\Theta(\tau)=0$, which corresponds precisely to $\xi_{2,1}$. The framework also yields a conditional uniqueness result for genus-2 symmetric surfaces and provides a pathway toward genus-$g$ extensions under similar symmetry constraints. The analysis combines Plateau theory in Meeks–Yau domains, conjugate minimal surfaces, and careful geometric control of geodesic-polygon boundaries in $\mathbb{S}^3$.
Abstract
The isometry group of the classical Lawson embedded minimal surface $ξ_{2,1}\subset \mathbb{S}^3$ of genus 2 is isomorphic to the group $O_{48}$ of isometries of a regular octahedron, of order 48. $O_{48}$ has a subgroup of index 3 isomorphic to the bidihedral group $D_{4h}=\mathbb{Z}_2\times D_4$, where $D_4$ is the dihedral group of order 8. We prove that $ξ_{2,1}$ is the unique closed embedded minimal surface of genus 2 in $\mathbb{S}^3$ whose isometry group contains $D_{4h}$.
