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Consequences of Dependent Dividing on Burden

Yuki Takahashi

TL;DR

The paper studies dependent dividing in $NTP_2$ theories and shows that the burden agrees with the $NIP$-$dp$-rank witnessed by $NIP$ formulas when dependent dividing holds. It then proves sub-additivity of the burden, first in the $NIP$-$dp$-minimal case and then for $NIP$-$dp$-finite theories, using adaptations of dp-rank techniques and finite-pattern arguments. An alternative proof via a reduct to a complete $NIP$ theory is provided. Finally, the work connects the burden to $VC^\ast$-density, showing that under dependent dividing, the burden lower bounds correspond to dual VC density for $NIP$ formulas.

Abstract

If $T$ has dependent dividing, then the burden agrees with the dp-rank witnessed by NIP formulas. We use this observation to prove that if $T$ has dependent dividing, then the burden is sub-additive. We also state a connection between the burden and the dual VC density.

Consequences of Dependent Dividing on Burden

TL;DR

The paper studies dependent dividing in theories and shows that the burden agrees with the --rank witnessed by formulas when dependent dividing holds. It then proves sub-additivity of the burden, first in the --minimal case and then for --finite theories, using adaptations of dp-rank techniques and finite-pattern arguments. An alternative proof via a reduct to a complete theory is provided. Finally, the work connects the burden to -density, showing that under dependent dividing, the burden lower bounds correspond to dual VC density for formulas.

Abstract

If has dependent dividing, then the burden agrees with the dp-rank witnessed by NIP formulas. We use this observation to prove that if has dependent dividing, then the burden is sub-additive. We also state a connection between the burden and the dual VC density.

Paper Structure

This paper contains 7 sections, 15 theorems, 18 equations.

Key Result

Theorem 1.6

Assume $T$ has dependent dividing and $k_1, k_2<\omega$. Let $a_1, a_2$ be tuples such that $\text{bdn}(a_i/A))\leq k_i$ for $i\in {1,2}$. Then, $\text{bdn}(a_1a_2/A)\leq k_1+k_2$.

Theorems & Definitions (39)

  • Definition 1.1
  • Definition 1.2
  • Definition 1.4
  • Definition 1.5
  • Theorem 1.6
  • Definition 2.1
  • Definition 2.2
  • Definition 2.3
  • Definition 2.4
  • Proposition 2.10
  • ...and 29 more