On the Diameter of Arrangements of Topological Disks
Aida Abiad, Boris Aronov, Mark de Berg, Julian Golak, Alexander Grigoriev, Freija van Lent
TL;DR
The paper studies the arrangement $\mathcal{A}(\mathcal{D})$ of $n$ topological disks with overlap number $\Delta=\max_{i,j} \Delta_{ij}$ and bounds the diameter of the dual graph $\mathcal{G}^*$ as a function of $n$ and $\Delta$, even when boundaries intersect arbitrarily. It proves a tight bound for two disks: $\diam(\mathcal{G}^*)=\max\{2,2\Delta\}$, and establishes general bounds for $n$ disks by first bounding the number of maximal faces $\mu(\mathcal{A})$ via $\mu(n,\Delta) \le n(\Delta+1)^{n(n-1)/2}$, then deriving $\xi(n,\Delta) \le 2n \cdot \min\{n,\Delta+1\} \cdot (\Delta+1)^{n(n-1)/2}$. The methods combine a detailed analysis of boundary intervals, component sets, and connectivity lemmas to control the arrangement's combinatorial structure, yielding results relevant to barrier-like path-crossing problems. The work leaves open whether $\mu(\mathcal{A})$ can be bounded polynomially in $n$ and $\Delta$, noting an almost-quadratic construction and conjecturing near-tightness.
Abstract
Let $\mathcal{D}=\{D_0,\ldots,D_{n-1}\}$ be a set of $n$ topological disks in the plane and let $\mathcal{A} := \mathcal{A}(\mathcal{D})$ be the arrangement induced by~$\mathcal{D}$. For two disks $D_i,D_j\in\mathcal{D}$, let $Δ_{ij}$ be the number of connected components of~$D_i\cap D_j$, and let $Δ:= \max_{i,j} Δ_{ij}$. We show that the diameter of $\mathcal{G}^*$, the dual graph of~$\mathcal{A}$, can be bounded as a function of $n$ and $Δ$. Thus, any two points in the plane can be connected by a Jordan curve that crosses the disk boundaries a number of times bounded by a function of~$n$ and~$Δ$. In particular, for the case of two disks we prove that the diameter of $\mathcal{G}^*$ is at most $\max\{2,2Δ\}$ and this bound is tight. % For the general case of $n>2$ disks, we show that the diameter of $\mathcal{G}^*$ is at most $2 n(Δ+1)^{n(n-1)/2} \min\{n,Δ+1\}$. We achieve this by proving that the number of maximal faces in $\mathcal{A}$ -- the faces whose ply is more than the ply of their neighboring faces -- is at most $n(Δ+1)^{n(n-1)/2}$, which is interesting in its own right.
