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Does the Convex Order Between the Distributions of Linear Functionals Imply the Convex Order Between the Probability Distributions Over $\mathbb R^d$?

Iosif Pinelis

Abstract

It is shown that the convex order between the distributions of linear functionals does not imply the convex order between the probability distributions over $\mathbb R^d$ if $d\ge2$. This stands in contrast with the well-known fact that any probability distribution in $\mathbb R^d$, for any $d\ge1$, is determined by the corresponding distributions of linear functionals. By duality, it follows that, for any $d\ge2$, not all convex functions from $\mathbb R^d$ to $\mathbb R$ can be represented as the limits of sums $\sum_{i=1}^k g_i\circ \ell_i$ of convex functions $g_i$ of linear functionals $\ell_i$ on $\mathbb R^d$.

Does the Convex Order Between the Distributions of Linear Functionals Imply the Convex Order Between the Probability Distributions Over $\mathbb R^d$?

Abstract

It is shown that the convex order between the distributions of linear functionals does not imply the convex order between the probability distributions over if . This stands in contrast with the well-known fact that any probability distribution in , for any , is determined by the corresponding distributions of linear functionals. By duality, it follows that, for any , not all convex functions from to can be represented as the limits of sums of convex functions of linear functionals on .

Paper Structure

This paper contains 1 theorem, 11 equations.

Key Result

Corollary 3

For any integer $d\ge2$, there is a convex function $f\colon\mathbb{R}^d\to\mathbb{R}$ that is not in the closed (say, with respect to the topology of pointwise convergence) convex hull $\overline{\operatorname{conv} F}$ of the set $F$ of all functions of the form $g\circ p_v$, where $g\colon\mathbb

Theorems & Definitions (3)

  • Remark 1
  • Remark 2
  • Corollary 3