The unit group and the 2-class number of some fields of the form $\mathbb{Q}(\sqrt{2}, \sqrt{pq}, \sqrt{ps})$ and $\mathbb{Q}(\sqrt{2}, \sqrt{pq}, \sqrt{ps}, \sqrt{-\ell})$
Moha Ben Taleb El Hamam
TL;DR
This work addresses the explicit computation of the unit group and the $2$-class number for multiquadratic fields of the form $L^+=\mathbb{Q}(\sqrt{2},\sqrt{pq},\sqrt{ps})$ and $L=\mathbb{Q}(\sqrt{2},\sqrt{pq},\sqrt{ps},\sqrt{-\ell})$, under specific congruence and Legendre-symbol conditions on three distinct primes $p,q,s$ and odd square-free $\ell$. The authors deploy Wada's method for multiquadratic fields, together with detailed norm calculations from biquadratic subextensions, to construct explicit fundamental units and to determine the $2$-class group structure. They present complete unit descriptions for both cases (case1 and case2) of the prime-symbol conditions, distinguishing the role of $\ell$ (whether $\ell=1$ or not) in the structure of $E_{L}$ and the presence of $\zeta_8$-factors. Additionally, they derive the $2$-class-number implications (e.g., $\mathrm{Cl}_2(\mathbb{L}^+) \cong (\mathbb{Z}/2\mathbb{Z})^2$ in one scenario) and discuss how these results inform the study of $2$-class field towers and cyclotomic $\mathbb{Z}_2$-extensions related to the base biquadratic fields.
Abstract
Let $\LL^+=\mathbb{Q}(\sqrt{2}, \sqrt{pq}, \sqrt{ps})$ and $\LL=\mathbb{Q}(\sqrt{2}, \sqrt{pq}, \sqrt{ps}, \sqrt{-\ell})$ be two fields, where $q$, $p$ and $s$ three different prime integers and $\ell\geq1$ be a positive odd square-free integer relatively prime to $q$, $p$ and $s$. The purpose of this paper is to show how one can proceed to perform the calculation of unit group of the fields of the form $\LL^+=\mathbb{Q}(\sqrt{2}, \sqrt{pq}, \sqrt{ps})$ and $\LL=\mathbb{Q}(\sqrt{2}, \sqrt{pq}, \sqrt{ps}, \sqrt{-\ell})$. More precisely, we compute the unit group and the $2$-class number of these fields whenever $p\equiv-s\equiv 5\pmod 8, q\equiv7\pmod 8 ~~ \text{and} ~~ \left(\frac{ p}{ q}\right)=\left(\frac{ p}{ s}\right)=\left(\frac{s}{ q}\right)=1$ and $\left(\frac{ p}{ q}\right)=\left(\frac{ p}{ s}\right),$ or $p\equiv-s\equiv 5\pmod 8, q\equiv7\pmod 8 ~~ \text{and} ~~ \left(\frac{ p}{ q}\right)=\left(\frac{ p}{ s}\right)=\left(\frac{s}{ q}\right)=-1$.
