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Energy shortcut of quantum protocols by optimal control

C. L. Latune, M. B. Puthuveedu Shebeek, D. Sugny, S. Guérin

Abstract

We introduce an energetically-optimal method inspired from Shortcut-To-Adiabaticity (STA) processes, named Quantum-Optimal-Shortcut-To-Energetics (QOSTE). QOSTE produces the same transformation as STA for a given protocol used in quantum technologies or thermodynamics, but at the lowest possible energy cost. We apply optimal control theory to analytically design the QOSTE controls for a qubit and show that the minimal energy cost is determined by the length of the geodesic in the rotating frame given by the original protocol. A numerical example in the case of a two-level quantum system under the Landau-Zener protocol illustrates the method. We observe a dramatic reduction in energy with respect to standard STA methods. Finally, using gradient-based optimization algorithms and highlighting the emerging trade-off between robustness and energy cost, we design robust QOSTE outperforming STA both in robustness and energy efficiency.

Energy shortcut of quantum protocols by optimal control

Abstract

We introduce an energetically-optimal method inspired from Shortcut-To-Adiabaticity (STA) processes, named Quantum-Optimal-Shortcut-To-Energetics (QOSTE). QOSTE produces the same transformation as STA for a given protocol used in quantum technologies or thermodynamics, but at the lowest possible energy cost. We apply optimal control theory to analytically design the QOSTE controls for a qubit and show that the minimal energy cost is determined by the length of the geodesic in the rotating frame given by the original protocol. A numerical example in the case of a two-level quantum system under the Landau-Zener protocol illustrates the method. We observe a dramatic reduction in energy with respect to standard STA methods. Finally, using gradient-based optimization algorithms and highlighting the emerging trade-off between robustness and energy cost, we design robust QOSTE outperforming STA both in robustness and energy efficiency.

Paper Structure

This paper contains 10 equations, 3 figures.

Figures (3)

  • Figure 1: Representation on the Bloch sphere of the excited state of (an arbitrary) $H_0(t)$ between $t=0$ and $t=t_f$, defining the so-called adiabatic trajectory (red points) and the length $L_{0,t_f}$. The adiabatic trajectory in the rotating picture with respect to $H_0(t)$ is plotted in green points, representing the length $\tilde{L}_{0,t_f}$ (which is shown to be equal to $L_{0,t_f}$, see Supplementary Material). The geodesic in such rotating picture, $\tilde{G}_{0,t_f}$, is represented in blue dashed line.
  • Figure 2: Trajectories of the qubit state when driven respectively by $H_{CD}(t) = H_0(t) + V_{CD}$ (in red), by $H(t) = H_0(t) + V_\text{QOSTE}(t)$ (in green), and by $H_0(t)$ (in blue). Inset: Amplitudes of the control functions for the QOSTE, $v_k(t) = \frac{1}{2\omega_i}{\rm Tr}[V_\text{QOSTE}(t)\sigma_k]$, $k=x$ (green dots), $k=y$ (green pluses), $k=z$ (green solid line), and for the counter-diabatic drive, $v_\text{CD}(t):= \frac{1}{2\omega_i}{\rm Tr}[V_\text{CD}(t)\sigma_y]$ (red solid line). We use $\Delta(t) = \Delta_0 +\Delta_d t/t_f$ with $\Delta_0/\omega = -10$, $\Delta_d/\omega = 20$ and $\omega t_f= 1$.
  • Figure 3: Plot of the average fidelity $\bar{F}$ against the energy cost ${\cal C} = \frac{\omega_i}{2}\int_0^{t_f} dt \vec{v}^2$ (normalized with ${\cal C}[V_\text{QOSTE}]$). The uncertainty range is $\epsilon = 0.15$, and $N_\eta = 7$. The green star indicates the average fidelity of QOSTE, ${\bar{F}} \simeq 0.989$, while the red star corresponds to the one of CD-STA, ${\bar{F}}\simeq 0.987$. Inset: Plot of the fidelity with respect to the target state $|\langle e_f|\psi_\eta(t_f)\rangle|^2$ as a function of the level of uncertainty represented by $\eta$, for the CD drive (in yellow dashed), for QOSTE (in black dotted) and finally for the GRAPE-designed robust QOSTE for the respective energy costs ${\cal C}/{\cal C}[V_\text{QOSTE}] =2.71$ (in green), ${\cal C}/{\cal C}[V_\text{QOSTE}] =3.87$ (in orange ), and ${\cal C}/{\cal C}[V_\text{QOSTE}] = 8.00$ (in blue).