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Many antipodes implies many neighbors

Stefan Steinerberger

TL;DR

This work addresses how many near-antipodal pairs force many near-neighbor pairs in planar point sets of diameter at most 1. It proves a universal lower bound: the number of ε-neighbors is at least a constant times $\varepsilon^{3/4}/(\log \varepsilon^{-1})^{1/4}$ times the number of antipodal pairs, with the optimal rate conjectured to be $\varepsilon^{1/2}$ and demonstrated by explicit examples. The authors develop a proof that combines geometric reductions to an ε-neighborhood of the boundary, a box-tiling discretization, and a linear-algebra bound via a matrix of antipodal possibilities, together with a graph-theoretic lemma to bound edge counts; the bound holds up to a logarithmic factor. They also discuss higher-dimensional extensions, provide sharp constructions achieving the conjectured rate, and place the result in the context of classical diameter-distance problems in extremal geometry. The methods offer a framework linking combinatorial geometry, spectral bounds, and graph-theoretic techniques to quantify local-global relationships in geometric configurations.

Abstract

Suppose $\left\{x_1, \dots, x_n\right\} \subset \mathbb{R}^2$ is a set of $n$ points in the plane with diameter $\leq 1$, meaning $\|x_i - x_j\| \leq 1$ for all $1 \leq i,j \leq n$. We show that if there are many `antipodes', these are pairs of points of with distance $\geq 1-\varepsilon$, then there are many neighbors, these are pairs of points that are distance $\leq \varepsilon$. More precisely, we prove that for some universal $c>0$, $$ \# \left\{(i,j): \|x_i - x_j\| \leq \varepsilon\right\} \geq \frac{c \cdot \varepsilon^{3/4}}{\left( \log \varepsilon^{-1} \right)^{1/4}}\cdot \# \left\{(i,j): \|x_i - x_j\| \geq 1- \varepsilon\right\}.$$ The inequality is very easy too prove with factor $\varepsilon^2$ and easy with $\varepsilon$. The optimal rate might be $\varepsilon^{1/2}$ which is attained by several examples.

Many antipodes implies many neighbors

TL;DR

This work addresses how many near-antipodal pairs force many near-neighbor pairs in planar point sets of diameter at most 1. It proves a universal lower bound: the number of ε-neighbors is at least a constant times times the number of antipodal pairs, with the optimal rate conjectured to be and demonstrated by explicit examples. The authors develop a proof that combines geometric reductions to an ε-neighborhood of the boundary, a box-tiling discretization, and a linear-algebra bound via a matrix of antipodal possibilities, together with a graph-theoretic lemma to bound edge counts; the bound holds up to a logarithmic factor. They also discuss higher-dimensional extensions, provide sharp constructions achieving the conjectured rate, and place the result in the context of classical diameter-distance problems in extremal geometry. The methods offer a framework linking combinatorial geometry, spectral bounds, and graph-theoretic techniques to quantify local-global relationships in geometric configurations.

Abstract

Suppose is a set of points in the plane with diameter , meaning for all . We show that if there are many `antipodes', these are pairs of points of with distance , then there are many neighbors, these are pairs of points that are distance . More precisely, we prove that for some universal , The inequality is very easy too prove with factor and easy with . The optimal rate might be which is attained by several examples.

Paper Structure

This paper contains 14 sections, 4 theorems, 31 equations, 5 figures.

Key Result

Theorem 1

There exists a universal constant $c>0$ such that for all $\varepsilon >0$ and any set $\left\{x_1, \dots, x_n \right\} \subset \mathbb{R}^2$ with diameter $\leq 1$, i.e. satisfying $\|x_i -x_j\| \leq 1$,

Figures (5)

  • Figure 1: $n$ points with $\sim n^2$ pairs of points at distance $\geq 1 - \varepsilon$ but also $\sim n^2$ pairs of points at distance $\leq \varepsilon$.
  • Figure 2: Left: a Reuleaux triangle with many points in the vertices, right: a regular polygon with points evenly spaced.
  • Figure 3: A sketch of a type of metric space where no such property holds: there can be many antipodes, pairs of points at distance $\geq 2$ while any pair of points is at least $1-$separated.
  • Figure 4: Reducing to a $\varepsilon-$neighborhood of the boundary and then breaking it into $\varepsilon/4 \times \varepsilon/4$ boxes.
  • Figure 5: A cartoon picture of the argument.

Theorems & Definitions (7)

  • Theorem
  • Lemma
  • proof
  • Lemma
  • proof
  • Lemma
  • proof