Table of Contents
Fetching ...

Odd spanning trees of a graph

Jingyu Zheng, Baoyindureng Wu

TL;DR

The paper addresses when graphs contain connected odd factors and odd spanning trees, and when complements contain odd spanning trees, focusing on graphs of even order. It employs the Nash-Williams–Tutte framework to construct connected odd factors from pairs of edge-disjoint spanning trees and uses case analyses to derive tight degree conditions for odd spanning trees, plus full classifications for split graphs and complements of triangle-free graphs. Key results include that every $4$-edge-connected graph of even order has a connected odd factor, and that a bound of $\delta(G)\ge \frac{n}{2}+1$ guarantees an odd spanning tree (with tightness shown via $K_{\frac{n}{2},\frac{n}{2}}$ when $n$ is multiple of $4$). The work also provides complete characterizations for split graphs and, for triangle-free graphs, precise conditions under which the complement admits an odd spanning tree, and it outlines several open problems with potential implications for graph complements and diameter-related properties.

Abstract

A graph $G=(V,E)$ is said to be odd (or even, resp.) if $d_G(v)$ is odd (or even, resp.) for any $v\in V$. Trivially, the order of an odd graph must be even. In this paper, we show that every 4-edge connected graph of even order has a connected odd factor. A spanning tree $T$ of $G$ is called a homeomorphically irreducible spanning tree (HIST by simply) if $T$ contains no vertex of degree two. Trivially, an odd spanning tree must be a HIST. In 1990, Albertson, Berman, Hutchinson, and Thomassen showed that every connected graph of order $n$ with $δ(G)\geq \min\{\frac n 2, 4\sqrt{2n}\}$ contains a HIST. We show that every complete bipartite graph with both parts being even has no odd spanning tree, thereby for any even integer $n$ divisible by 4, there exists a graph of order $n$ with the minimum degree $\frac n 2$ having no odd spanning tree. Furthermore, we show that every graph of order $n$ with $δ(G)\geq \frac n 2 +1$ has an odd spanning tree. We also characterize all split graphs having an odd spanning tree. As an application, for any graph $G$ with diameter at least 4, $\overline{G}$ has a spanning odd double star. Finally, we also give a necessary and sufficient condition for a triangle-free graph $G$ whose complement contains an odd spanning tree. A number of related open problems are proposed.

Odd spanning trees of a graph

TL;DR

The paper addresses when graphs contain connected odd factors and odd spanning trees, and when complements contain odd spanning trees, focusing on graphs of even order. It employs the Nash-Williams–Tutte framework to construct connected odd factors from pairs of edge-disjoint spanning trees and uses case analyses to derive tight degree conditions for odd spanning trees, plus full classifications for split graphs and complements of triangle-free graphs. Key results include that every -edge-connected graph of even order has a connected odd factor, and that a bound of guarantees an odd spanning tree (with tightness shown via when is multiple of ). The work also provides complete characterizations for split graphs and, for triangle-free graphs, precise conditions under which the complement admits an odd spanning tree, and it outlines several open problems with potential implications for graph complements and diameter-related properties.

Abstract

A graph is said to be odd (or even, resp.) if is odd (or even, resp.) for any . Trivially, the order of an odd graph must be even. In this paper, we show that every 4-edge connected graph of even order has a connected odd factor. A spanning tree of is called a homeomorphically irreducible spanning tree (HIST by simply) if contains no vertex of degree two. Trivially, an odd spanning tree must be a HIST. In 1990, Albertson, Berman, Hutchinson, and Thomassen showed that every connected graph of order with contains a HIST. We show that every complete bipartite graph with both parts being even has no odd spanning tree, thereby for any even integer divisible by 4, there exists a graph of order with the minimum degree having no odd spanning tree. Furthermore, we show that every graph of order with has an odd spanning tree. We also characterize all split graphs having an odd spanning tree. As an application, for any graph with diameter at least 4, has a spanning odd double star. Finally, we also give a necessary and sufficient condition for a triangle-free graph whose complement contains an odd spanning tree. A number of related open problems are proposed.

Paper Structure

This paper contains 5 sections, 12 theorems, 47 equations.

Key Result

Theorem 1.1

Every connected graph of even order has a vertex partition into sets inducing subgraphs with all degrees odd.

Theorems & Definitions (27)

  • Theorem 1.1: Scott2001
  • Theorem 2.1: Nash-Williams1961Tutte1961
  • Theorem 2.2
  • proof
  • Lemma 2.3
  • proof
  • Proposition 2.4
  • proof
  • Proposition 2.5
  • proof
  • ...and 17 more