Divergence-free drifts decrease concentration
Elias Hess-Childs, Renaud Raquépas, Keefer Rowan
TL;DR
This work establishes a universal comparison principle for concentration between advection-diffusion with bounded divergence-free drifts and the heat equation on $\mathbb{R}^d$: if $\mu \preceq \nu$ with $\nu$ symmetric decreasing, then $\mathcal{P}_t^u \mu \preceq e^{t\Delta}\nu$ for all $t\ge0$, for any bounded divergence-free drift $u$. Consequently, for symmetric decreasing initial data, the advection-diffusion evolution has at least as large variance and entropy and at most as large $L^p$ norms as the pure-diffusion evolution (with no prefactor), with precise consequences for the entire spectrum of concentration via the modulus of absolute continuity. The analysis hinges on symmetric decreasing rearrangements and a split-operator approach that alternates diffusion and advection, leveraging the fact that advection preserves concentration while diffusion is order-preserving in the rearrangement order. A torus $\mathbb{T}^d$ counterexample shows the inequality can fail on compact manifolds due to broken rotational symmetry, highlighting the domain’s geometry as a fundamental factor. Overall, the results provide a robust, quantitative framework for understanding how divergence-free drifts modulate concentration, variance, entropy, and $L^p$ norms in passive scalars relevant to turbulence and mixing.
Abstract
We show that bounded divergence-free vector fields $u : [0,\infty) \times \mathbb{R}^d \to\mathbb{R}^d$ decrease the ''concentration'', quantified by the modulus of absolute continuity with respect to the Lebesgue measure, of solutions to the associated advection-diffusion equation when compared to solutions to the heat equation. In particular, for symmetric decreasing initial data, the solution to the advection-diffusion equation has (without a prefactor constant) larger variance, larger entropy, and smaller $L^p$ norms for all $p \in [1,\infty]$ than the solution to the heat equation. We also note that the same is not true on $\mathbb{T}^d$.
