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Divergence-free drifts decrease concentration

Elias Hess-Childs, Renaud Raquépas, Keefer Rowan

TL;DR

This work establishes a universal comparison principle for concentration between advection-diffusion with bounded divergence-free drifts and the heat equation on $\mathbb{R}^d$: if $\mu \preceq \nu$ with $\nu$ symmetric decreasing, then $\mathcal{P}_t^u \mu \preceq e^{t\Delta}\nu$ for all $t\ge0$, for any bounded divergence-free drift $u$. Consequently, for symmetric decreasing initial data, the advection-diffusion evolution has at least as large variance and entropy and at most as large $L^p$ norms as the pure-diffusion evolution (with no prefactor), with precise consequences for the entire spectrum of concentration via the modulus of absolute continuity. The analysis hinges on symmetric decreasing rearrangements and a split-operator approach that alternates diffusion and advection, leveraging the fact that advection preserves concentration while diffusion is order-preserving in the rearrangement order. A torus $\mathbb{T}^d$ counterexample shows the inequality can fail on compact manifolds due to broken rotational symmetry, highlighting the domain’s geometry as a fundamental factor. Overall, the results provide a robust, quantitative framework for understanding how divergence-free drifts modulate concentration, variance, entropy, and $L^p$ norms in passive scalars relevant to turbulence and mixing.

Abstract

We show that bounded divergence-free vector fields $u : [0,\infty) \times \mathbb{R}^d \to\mathbb{R}^d$ decrease the ''concentration'', quantified by the modulus of absolute continuity with respect to the Lebesgue measure, of solutions to the associated advection-diffusion equation when compared to solutions to the heat equation. In particular, for symmetric decreasing initial data, the solution to the advection-diffusion equation has (without a prefactor constant) larger variance, larger entropy, and smaller $L^p$ norms for all $p \in [1,\infty]$ than the solution to the heat equation. We also note that the same is not true on $\mathbb{T}^d$.

Divergence-free drifts decrease concentration

TL;DR

This work establishes a universal comparison principle for concentration between advection-diffusion with bounded divergence-free drifts and the heat equation on : if with symmetric decreasing, then for all , for any bounded divergence-free drift . Consequently, for symmetric decreasing initial data, the advection-diffusion evolution has at least as large variance and entropy and at most as large norms as the pure-diffusion evolution (with no prefactor), with precise consequences for the entire spectrum of concentration via the modulus of absolute continuity. The analysis hinges on symmetric decreasing rearrangements and a split-operator approach that alternates diffusion and advection, leveraging the fact that advection preserves concentration while diffusion is order-preserving in the rearrangement order. A torus counterexample shows the inequality can fail on compact manifolds due to broken rotational symmetry, highlighting the domain’s geometry as a fundamental factor. Overall, the results provide a robust, quantitative framework for understanding how divergence-free drifts modulate concentration, variance, entropy, and norms in passive scalars relevant to turbulence and mixing.

Abstract

We show that bounded divergence-free vector fields decrease the ''concentration'', quantified by the modulus of absolute continuity with respect to the Lebesgue measure, of solutions to the associated advection-diffusion equation when compared to solutions to the heat equation. In particular, for symmetric decreasing initial data, the solution to the advection-diffusion equation has (without a prefactor constant) larger variance, larger entropy, and smaller norms for all than the solution to the heat equation. We also note that the same is not true on .

Paper Structure

This paper contains 14 sections, 27 theorems, 128 equations.

Key Result

Theorem 1.7

Let $\mu, \nu \in \mathcal{M}_+(\mathds{R}^d)$ and let $u : [0,\infty) \times \mathds{R}^d\to \mathds{R}^d$ be a bounded, measurable, divergence-free vector field. If $\nu$ is symmetric decreasing and $\mu \preceq \nu$, then for all $t\geq 0$.

Theorems & Definitions (63)

  • Definition 1.1
  • Remark 1.2
  • Definition 1.3
  • Definition 1.4
  • Remark 1.5
  • Definition 1.6
  • Theorem 1.7
  • Remark 1.8
  • Remark 1.9
  • Corollary 1.10
  • ...and 53 more