Table of Contents
Fetching ...

Beilinson's conjecture on K3 surfaces with an involution

Kalyan Banerjee

TL;DR

The paper proves Beilinson's conjecture for certain K3 surfaces $S$ defined over $\bar{\mathbb{Q}}$ equipped with an involution $i$ such that the quotient $S/i$ is isomorphic to $\mathbb{P}^2$ with a genus six branch component and infinitely many rational curves on $S$. The key strategy combines Voisin's observation that $i_*$ acts trivially on the Albanese kernel $A_0(S)$ with a Roitman-type finite-dimensionality analysis to show the relevant degree-zero Chow maps factor through the Albanese and vanish. A central technical step is showing that the image of the correspondence $\Delta_S-\mathrm{Gr}(i)$ is finite-dimensional, achieved via ramification considerations of a ramified double cover and dimension counts of Jacobian fibrations. Under these hypotheses, the Albanese kernel $A_0(S)$ is trivial, establishing Beilinson's conjecture for such $S$ and highlighting the role of ramification and abundant rational curves in countable-field settings.

Abstract

In this note we prove that the Beilinson conjecture holds for certain examples of K3 surfaces over $\bar {\mathbb{Q}}$ equipped with an involution, when the quotient of the surface by the involution is the projective plane branched along a sextic.

Beilinson's conjecture on K3 surfaces with an involution

TL;DR

The paper proves Beilinson's conjecture for certain K3 surfaces defined over equipped with an involution such that the quotient is isomorphic to with a genus six branch component and infinitely many rational curves on . The key strategy combines Voisin's observation that acts trivially on the Albanese kernel with a Roitman-type finite-dimensionality analysis to show the relevant degree-zero Chow maps factor through the Albanese and vanish. A central technical step is showing that the image of the correspondence is finite-dimensional, achieved via ramification considerations of a ramified double cover and dimension counts of Jacobian fibrations. Under these hypotheses, the Albanese kernel is trivial, establishing Beilinson's conjecture for such and highlighting the role of ramification and abundant rational curves in countable-field settings.

Abstract

In this note we prove that the Beilinson conjecture holds for certain examples of K3 surfaces over equipped with an involution, when the quotient of the surface by the involution is the projective plane branched along a sextic.

Paper Structure

This paper contains 2 sections, 8 theorems, 20 equations.

Key Result

Theorem 1.1

Let $S$ be a smooth K3 surface such that there is an involution $i$ on $S$ and $S/i$ is isomorphic to the projective plane. The branch locus of the involution contains a unique component of genus six. Suppose further that $S$ contains infinitely many rational curves. Then the Beilinson conjecture ho

Theorems & Definitions (13)

  • Theorem 1.1
  • Definition 2.1
  • Theorem 2.2
  • proof
  • Lemma 2.3
  • proof
  • Lemma 2.4
  • Lemma 2.5
  • proof
  • Theorem 2.6
  • ...and 3 more