The Graph Coloring Game on $4\times n$-Grids
Caroline Brosse, Nicolas Martins, Nicolas Nisse, Rudini Sampaio
TL;DR
This work resolves the four-by-n grid case for the graph coloring game by proving χ_g(P_4 × P_n) ≤ 4 for all n and exactly χ_g(P_4 × P_n) = 4 for all n ≥ 18, using a novel block-based strategy. Central to the method is a detailed combinatorial framework of blocks, borders, and local configurations that preserves a robust invariant under Bob’s moves, enabling Alice to color the entire grid with four colors. The approach introduces concepts such as safe, sound, and sick vertices and a taxonomy of border configurations (alpha, beta, gamma, delta, pi) plus seven particular configurations to handle edge scenarios, culminating in a long, case-heavy but systematic proof of correctness. The results illuminate the structure of adversarial coloring on structured grids and point to interesting avenues for general m,n and related graph classes, with several open questions guiding future work.
Abstract
The graph coloring game is a famous two-player game (re)introduced by Bodlaender in $1991$. Given a graph $G$ and $k \in \mathbb{N}$, Alice and Bob alternately (starting with Alice) color an uncolored vertex with some color in $\{1,\cdots,k\}$ such that no two adjacent vertices receive a same color. If eventually all vertices are colored, then Alice wins and Bob wins otherwise. The game chromatic number $χ_g(G)$ is the smallest integer $k$ such that Alice has a winning strategy with $k$ colors in $G$. It has been recently (2020) shown that, given a graph $G$ and $k\in \mathbb{N}$, deciding whether $χ_g(G)\leq k$ is PSPACE-complete. Surprisingly, this parameter is not well understood even in ``simple" graph classes. Let $P_n$ denote the path with $n\geq 1$ vertices. For instance, in the case of Cartesian grids, it is easy to show that $χ_g(P_m \times P_n) \leq 5$ since $χ_g(G)\leq Δ+1$ for any graph $G$ with maximum degree $Δ$. However, the exact value is only known for small values of $m$, namely $χ_g(P_1\times P_n)=3$, $χ_g(P_2\times P_n)=4$ and $χ_g(P_3\times P_n) =4$ for $n\geq 4$ [Raspaud, Wu, 2009]. Here, we prove that, for every $n\geq 18$, $χ_g(P_4\times P_n) =4$.
