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Coalescence Probabilities of Cycle Products

Holden Mui

TL;DR

The paper provides a purely combinatorial proof for the probability that $1,\dots,k$ lie in the same cycle of a product of two random $n$-cycles, giving the explicit formula $P = \frac{1}{k} + \frac{4 (-1)^n}{ \binom{2k}{k}} \sum_{\substack{1 \le i \le k-1 \\ i \not\equiv n \bmod 2}} \binom{2k-1}{k+i} \left(\frac{1}{n+i+1} - \frac{1}{n-i}\right)$. The authors develop a diagrammatic, bijective framework by mapping colored $n$-cycles to pairs of Eulerian tours on degree-$(s_1,\dots,s_r)$ digraphs and extend it to count $t$-colored $k$-subsets of $r$-colored $n$-cycles via colored strips, yielding exact counting formulas. They then transform these counts to a sum suitable for partial fraction decomposition, derive auxiliary expressions $A(n,k)$ and $B(n,k)$, and, using four key identities, obtain the closed form that exhibits the probability as a rational function in $n(n+1)$ with a parity dependence. This combinatorial approach corroborates known results from character theory, clarifies parity-driven structure, and suggests avenues for generalizing to more refined cycle-type partitions, with potential implications for understanding cycle-coalescence phenomena in random permutations.

Abstract

Generalizing a formula of Stanley, we prove combinatorially that the probability that $1, 2, \dots, k$ are contained in the same cycle of a product of two random $n$-cycles is \[\frac{1}{k} + \frac{4 (-1)^n}{ \binom{2k}{k}} \sum_{\substack{1 \leq i \leq k-1 \\ i \not\equiv n \bmod 2}} \binom{2k-1}{k+i} \left(\frac{1}{n+i+1} - \frac{1}{n-i}\right).\]

Coalescence Probabilities of Cycle Products

TL;DR

The paper provides a purely combinatorial proof for the probability that lie in the same cycle of a product of two random -cycles, giving the explicit formula . The authors develop a diagrammatic, bijective framework by mapping colored -cycles to pairs of Eulerian tours on degree- digraphs and extend it to count -colored -subsets of -colored -cycles via colored strips, yielding exact counting formulas. They then transform these counts to a sum suitable for partial fraction decomposition, derive auxiliary expressions and , and, using four key identities, obtain the closed form that exhibits the probability as a rational function in with a parity dependence. This combinatorial approach corroborates known results from character theory, clarifies parity-driven structure, and suggests avenues for generalizing to more refined cycle-type partitions, with potential implications for understanding cycle-coalescence phenomena in random permutations.

Abstract

Generalizing a formula of Stanley, we prove combinatorially that the probability that are contained in the same cycle of a product of two random -cycles is
Paper Structure (6 sections, 15 theorems, 68 equations, 12 figures, 1 table)

This paper contains 6 sections, 15 theorems, 68 equations, 12 figures, 1 table.

Key Result

Theorem 1.1

Let $k$ and $n$ be positive integers with $k \leq n$. The probability that $1, 2, \dots, k$ are contained in the same cycle of a product of two random $n$-cycles is

Figures (12)

  • Figure 1: A 6-colored 16-cycle $\sigma$ and the colored cycles of $\sigma \tau$.
  • Figure 2: A 3-colored 5-subset of a 6-colored 16-cycle.
  • Figure 3: The bijection in \ref{['theorem:bijection']}.
  • Figure 4: A degree-$(5, 2, 4, 1, 2, 2)$ digraph.
  • Figure 5: The bijection in \ref{['lemma:bijectionstep1']}.
  • ...and 7 more figures

Theorems & Definitions (35)

  • Theorem 1.1
  • Lemma 2.1
  • Claim 2.2
  • proof
  • Claim 2.3
  • proof
  • proof : Proof of \ref{['lemma:coalescence']}
  • Theorem 3.1
  • Lemma 3.2
  • proof
  • ...and 25 more