Taut visibility domains are not necessarily Kobayashi complete
Rumpa Masanta
TL;DR
The paper resolves Banik's question by constructing, for each $n\ge 2$, a bounded domain $\Omega\subset \mathbb{C}^n$ with $0\in\partial\Omega$, smooth boundary away from $0$, that is taut and a visibility domain with respect to the Kobayashi distance, yet $(\Omega,K_\Omega)$ is not Cauchy-complete. The construction blends a plurisubharmonic exhaustion on a product domain, a carefully chosen set $X$, a sequence $(x_\nu)$, and a PSH function $u$ to define $\Omega$, ensuring tautness and visibility through local Goldilocks points, while producing a $K_\Omega$-Cauchy sequence that does not converge in $\Omega$. This demonstrates that taut visibility does not imply Kobayashi completeness, sharpening the understanding of Kobayashi geometry in several complex variables and providing explicit counterexamples across dimensions.
Abstract
We answer a question asked recently by Banik in the negative by showing that for each $n\geq 2$, there exists a taut visibility domain in $\mathbb{C}^n$ that is not Kobayashi complete. The domains that we produce are bounded and have boundaries that are very regular away from a single point.
