The special unitary groups $SU(2n)$ as framed manifolds
Haruo Minami
TL;DR
The paper investigates how twisting the left-invariant framing on framed Lie groups alters the complex Adams $e$-invariant, showing that for $G=SU(2n)$ a specific twist by the real representation $\rho$ yields a nonzero value, namely $e_\mathbb{C}([SU(2n), \mathscr{L}^{(n-1)\rho}]) = (-1)^{n-1} \frac{B_{n^2}}{2n^2}$, while the untwisted case vanishes. It develops a tensor-product decomposition of a canonical complex line bundle $E$ over $G/S$ arising from a circle subgroup, and demonstrates that the induced stable framing corresponds to $\mathscr{L}^{(n-1)\rho}$, enabling an explicit computation of the $e$-invariant via known formulas (LS). The method extends to the quotient $SU(2n+1)/C$ with induced framing, obtaining $e_\mathbb{C}([SU(2n+1)/C, \mathscr{L}_C]) = -\frac{B_{n^2+n}}{2(n^2+n)}$. Collectively, the results show that suitable framing twists convert zero $e$-invariants into generators of the image of $e_\mathbb{C}$, and provide explicit representatives tied to Bernoulli numbers, revealing a robust link between representation-theoretic twists and bordism invariants.
Abstract
Let $[SU(2n), \mathscr{L}]$ denote the bordism class of $SU(2n)$ $(n\ge 2)$ equipped with its left invariant framing $\mathscr{L}$. Then it is well known that $e_\mathbb{C}([SU(2n), \mathscr{L}])=0$ where $e_\mathbb{C}$ denotes the complex Adams $e$-invariant. In this note we show that replacing $\mathscr{L}$ by the framing obtained by twisting it by a specific map the zero value of $e_\mathbb{C}([SU(2n), \mathscr{L}])$ can be transformed into a generator of $\mathrm{Im} \, e_\mathbb{C}$ which is isomorphic to a cyclic group. In addition we show that the same procedure affords an analogous result for a quotient of $SU(2n+1)$ by a circle subgroup which inherits a canonical framing from $SU(2n+1)$ in the usual way. .
