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Linking numbers of Montesinos links

Hyoungjun Kim, Sungjong No, Hyungkee Yoo

Abstract

The linking number of an oriented two-component link is an invariant indicating how intertwined the two components are. Tuler proved that the linking number of a two-component rational $\frac{p}{q}$-link is $$\sum^{\frac{|p|}{2}}_{k=1} (-1)^{\big\lfloor (2k-1) \frac{q}{p} \big\rfloor }.$$ In this paper, we provide a simple proof the above result, and introduce the numerical algorithm to find linking numbers of rational links. Using this result, we find linking numbers between any two components in a Montesinos link.

Linking numbers of Montesinos links

Abstract

The linking number of an oriented two-component link is an invariant indicating how intertwined the two components are. Tuler proved that the linking number of a two-component rational -link is In this paper, we provide a simple proof the above result, and introduce the numerical algorithm to find linking numbers of rational links. Using this result, we find linking numbers between any two components in a Montesinos link.
Paper Structure (6 sections, 5 theorems, 24 equations, 9 figures)

This paper contains 6 sections, 5 theorems, 24 equations, 9 figures.

Key Result

Proposition 1

The linking number of an oriented rational link $R_{p/q}$ is where $p$ and $q$ are relatively prime integers and $p$ is even.

Figures (9)

  • Figure 1: Assigning the signs of crossings in a link.
  • Figure 2: Operations for rational tangles.
  • Figure 3: Pillowcase forms of rational tangles with $\frac{2}{1}$, $-\frac{4}{3}$ and $\frac{5}{3}$.
  • Figure 4: The structure of a Montesinos link and the example of $M \left( \left. \frac{3}{2}, -\frac{3}{1}, \frac{5}{3} \right| 2 \right)$.
  • Figure 5: The construction of the branched covering of $\partial P$.
  • ...and 4 more figures

Theorems & Definitions (11)

  • Proposition 1
  • proof : Alternative proof of Proposition \ref{['prop:link']}
  • Proposition 2
  • proof
  • Example
  • Theorem 3
  • proof
  • Theorem 4
  • proof
  • Theorem 5
  • ...and 1 more