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Envy-Free House Allocation with Minimum Subsidy

Davin Choo, Yan Hao Ling, Warut Suksompong, Nicholas Teh, Jian Zhang

TL;DR

It is shown that computing an envy-free allocation with minimum subsidy is NP-hard in general, but can be done efficiently if $m$ differs from $n$ by an additive constant or if the agents have identical utilities.

Abstract

House allocation refers to the problem where $m$ houses are to be allocated to $n$ agents so that each agent receives one house. Since an envy-free house allocation does not always exist, we consider finding such an allocation in the presence of subsidy. We show that computing an envy-free allocation with minimum subsidy is NP-hard in general, but can be done efficiently if $m$ differs from $n$ by an additive constant or if the agents have identical utilities.

Envy-Free House Allocation with Minimum Subsidy

TL;DR

It is shown that computing an envy-free allocation with minimum subsidy is NP-hard in general, but can be done efficiently if differs from by an additive constant or if the agents have identical utilities.

Abstract

House allocation refers to the problem where houses are to be allocated to agents so that each agent receives one house. Since an envy-free house allocation does not always exist, we consider finding such an allocation in the presence of subsidy. We show that computing an envy-free allocation with minimum subsidy is NP-hard in general, but can be done efficiently if differs from by an additive constant or if the agents have identical utilities.
Paper Structure (7 sections, 7 theorems, 7 equations, 1 table)

This paper contains 7 sections, 7 theorems, 7 equations, 1 table.

Key Result

Theorem 3.1

The problem of computing a minimum-subsidy envy-free outcome is NP-hard.

Theorems & Definitions (15)

  • Definition 2.1
  • Example 2.2
  • Definition 2.3
  • Theorem 3.1
  • proof
  • Theorem 4.1
  • Proposition 4.2
  • Lemma 4.3: halpern2019fair
  • Lemma 4.4: Lemma 3 of barman2022achieving
  • Lemma 4.5
  • ...and 5 more