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Pach's animal problem within the bounding box

Martin Tancer

Abstract

A collection of unit cubes with integer coordinates in $\mathbb R^3$ is an animal if its union is homeomorphic to the 3-ball. Pach's animal problem asks whether any animal can be transformed to a single cube by adding or removing cubes one by one in such a way that any intermediate step is an animal as well. Here we provide an example of an animal that cannot be transformed to a single cube this way within its bounding box.

Pach's animal problem within the bounding box

Abstract

A collection of unit cubes with integer coordinates in is an animal if its union is homeomorphic to the 3-ball. Pach's animal problem asks whether any animal can be transformed to a single cube by adding or removing cubes one by one in such a way that any intermediate step is an animal as well. Here we provide an example of an animal that cannot be transformed to a single cube this way within its bounding box.
Paper Structure (17 sections, 6 theorems, 1 equation, 17 figures)

This paper contains 17 sections, 6 theorems, 1 equation, 17 figures.

Key Result

Theorem 1

There is an animal $A$ such that it cannot be transformed to a single cube by additions or removals of cubes which are inside the bounding box of $A$. In fact, if we remove a cube from $A$ or add a cube to $A$ contained inside the bounding box, we never obtain an animal.

Figures (17)

  • Figure 1: Furch's knotted ball. All displayed cubes are removed from the box except the dark one. The picture we provide here is very similar to a picture in ziegler98.
  • Figure 2: The first expansion of a 2-dimensional example.
  • Figure 3: The second expansion of a 2-dimensional example. The squares on both sides of the picture should be understood as unit squares. The dimensions of the right right picture are $17 \times 27$ but it is shrunk due to space constraints.
  • Figure 4: Left: Joining the construction from Figure \ref{['f:second_expansion']} with its mirror copy. Now the dimensions are $17 \times 55$. Right: After adding or removing the squares in green we still have a 2-dimensional animal.
  • Figure 5: U-turn.
  • ...and 12 more figures

Theorems & Definitions (10)

  • Theorem 1
  • Lemma 2
  • Lemma 3
  • proof
  • Lemma 4
  • Lemma 5
  • Lemma 6
  • proof : Proof of Lemma \ref{['l:red']}.
  • proof : Proof of Lemma \ref{['l:white']}.
  • proof : Proof of Lemma \ref{['l:black']}