Almost all quadratic twists of an elliptic curve have no integral points
Tim Browning, Stephanie Chan
TL;DR
The paper proves that almost all quadratic twists $E_D$ of a fixed elliptic curve $E: y^2=x^3+Ax+B$ have no integral points, when $D$ runs over square-free integers, with a conditional upper bound in the presence of partial $2$-torsion (weak Hall–Lang conjecture) and an unconditional bound when no rational $2$-torsion exists. The authors develop a comprehensive strategy combining Mordell’s construction of binary quartic forms from integral points with Cremona’s reduction theory to translate the problem into counting rational points on a singular cubic surface, and they control the counts via detailed Heath–Brown type character-sum estimates. They also derive higher-moments bounds for the number of integral points across the twists, using Smith’s Selmer-rank results and Szpiro ratio arguments to bound exponential ranks and Selmer-related quantities. The work handles both full and partial $2$-torsion cases, providing a robust framework that links geometric reduction, arithmetic of quartic forms, and analytic number theory to establish density-zero results with quantitative bounds, and thereby informs the distribution of integral points and Selmer elements in quadratic twist families.
Abstract
For a given elliptic curve E in short Weierstrass form, we show that almost all quadratic twists E_D have no integral points, as D ranges over square-free integers ordered by size. Our result is conditional on a weak form of the Hall-Lang conjecture in the case that E has partial 2-torsion. The proof uses a correspondence of Mordell and the reduction theory of binary quartic forms in order to transfer the problem to counting rational points of bounded height on a certain singular cubic surface, together with extensive use of cancellation in character sum estimates, drawn from Heath-Brown's analysis of Selmer group statistics for the congruent number curve.
