Fast winning strategies in a generalized van der Waerden game
Hannah Alpert, Liam Barham, Brian Freidin, Ian Tan, Alexandra Weiner
TL;DR
The paper studies fast winning strategies in a generalized van der Waerden Maker–Breaker game on $\mathbb{N}$, where Maker wins by claiming a homothetic copy $aS+b$ of a finite set $S$. It combines a Hales–Jewett–based upper bound with constructive tree arguments to obtain optimal move counts for small $|S|$, and symmetry-based arguments to rule out fast wins for larger $|S|$. The main contributions are the exact move counts $C_n=n$ for $n\le 3$, $C_4=5$ with a complete characterization of $4$-move-$S$ sets, and a complete resolution showing no $|S|$-move strategy when $|S|\ge 5$, plus explicit tree constructions for size four. These results sharpen the understanding of how quickly Maker can force an affine-copy completion in this affine-geometry flavored combinatorial game, and illustrate the role of symmetry and constructive trees in designing winning strategies.
Abstract
Consider the following Maker-Breaker game. Fix a finite subset $S\subset\mathbb{N}$ of the naturals. The players Maker and Breaker take turns choosing previously unclaimed natural numbers. Maker wins by eventually building a homothetic copy $aS+b$ of $S$, where $a\in\mathbb{N}\setminus\{0\}$ and $b\in\mathbb{Z}$. This is a generalization of the van der Waerden game analyzed by Beck. By the Hales-Jewett theorem, there exists a constant $c$ depending only on $|S|$ such that Maker can win in $c$ or less moves. We show that Maker can win in $|S|$ moves if $|S|\leq 3$. When $|S|=4$, we show that Maker can always win in $5$ or less moves and describe all $S$ such that Maker can win in $4$ moves. If $|S|\geq 5$, Maker has no winning strategy in $|S|$ moves.
