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Finitely generated bimodules over Weyl algebras

Niels Lauritzen, Jesper Funch Thomsen

Abstract

Let $A$ be the $n$-th Weyl algebra over a field of characteristic zero, and $\varphi:A\rightarrow A$ an endomorphism with $S = \varphi(A)$. We prove that if $A$ is finitely generated as a left or right $S$-module, then $S = A$. The proof involves reduction to large positive characteristics. By holonomicity, $A$ is always finitely generated as an $S$-bimodule. Moreover, if this bimodule property could be transferred into a similar property in large positive characteristics, then we could again conclude that $A=S$. The latter would imply the Dixmier Conjecture.

Finitely generated bimodules over Weyl algebras

Abstract

Let be the -th Weyl algebra over a field of characteristic zero, and an endomorphism with . We prove that if is finitely generated as a left or right -module, then . The proof involves reduction to large positive characteristics. By holonomicity, is always finitely generated as an -bimodule. Moreover, if this bimodule property could be transferred into a similar property in large positive characteristics, then we could again conclude that . The latter would imply the Dixmier Conjecture.
Paper Structure (11 sections, 18 theorems, 48 equations)

This paper contains 11 sections, 18 theorems, 48 equations.

Key Result

Proposition 1.1

Let $R$ be an integral domain with $\operatorname{Jac}(R) = \{0\}$, $X = \operatorname{Specm}(R)$ and $X_r = \{\mathfrak{m}\in X\mid r\notin \mathfrak{m}\}$ for $r\in R$. Then is a filter on $X$. Let $\mathcal{U}$ be an ultrafilter on $X$ containing $\mathcal{F}$. Then $\prod_{\mathcal{U}} R/\mathfrak{m}$ contains the fraction field of $R$.

Theorems & Definitions (38)

  • Proposition 1.1
  • proof
  • Lemma 1.2
  • proof
  • Proposition 2.1
  • proof
  • Definition 2.2
  • Theorem 2.3
  • proof
  • Corollary 2.4
  • ...and 28 more