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Convex bodies with centrally symmetric sections

E. Morales-Amaya

TL;DR

The paper studies Barker-Larman’s ellipsoid characterization in the setting of central symmetry. It defines a jointly sufficient framework with a central ball $B$ inside $K$ that is suitable for $K$ and requires that every supporting hyperplane of $B$ cuts $K$ into a centrally symmetric section; under these hypotheses, if $K$ is centrally symmetric and strictly convex with center $O$ and $O\notin B$, then $K$ must be an ellipsoid. The authors prove the result first in dimension $3$, showing that plentiful shadow boundaries and affine axes of symmetry force $K$ to be an ellipsoid, and then extend the argument to $n>3$ via a projection-induction method. This work advances the Barker-Larman program by confirming a significant special case where central symmetry yields ellipsoidality.

Abstract

Let $K\subset \mathbb{R}^n$ be a convex body, $n\geq 3$. We say that $K$ satisfies the Barker-Larman condition if there exists a ball $B$ in the interior of $K$ such that for every suppor hyperplane $Π$ of $B$, the section $Π\cap K$ is a centrally symmetric set. Barker and Larman conjectured that the Barker-Larman condition characterizes the ellipsoid. In this work we prove an special case of such conjecture, in particular, we assume that the convex body $K$ is centrally symmetric. Our main result is the following: Let $K$ be a centrally symmetric and strictly convex body, with center at $O$, and let $B$ be a ball in the interior of $K$ and not containing $O$: If $K$ satisfies the Barker-Larman condition with respect to $B$ and $B$ is suitable for $K$ (intuitively, $B$ is suitable for $K$ if the boundary of $B$ is not very close to the boundary of $K$), then $K$ is an ellipsoid.

Convex bodies with centrally symmetric sections

TL;DR

The paper studies Barker-Larman’s ellipsoid characterization in the setting of central symmetry. It defines a jointly sufficient framework with a central ball inside that is suitable for and requires that every supporting hyperplane of cuts into a centrally symmetric section; under these hypotheses, if is centrally symmetric and strictly convex with center and , then must be an ellipsoid. The authors prove the result first in dimension , showing that plentiful shadow boundaries and affine axes of symmetry force to be an ellipsoid, and then extend the argument to via a projection-induction method. This work advances the Barker-Larman program by confirming a significant special case where central symmetry yields ellipsoidality.

Abstract

Let be a convex body, . We say that satisfies the Barker-Larman condition if there exists a ball in the interior of such that for every suppor hyperplane of , the section is a centrally symmetric set. Barker and Larman conjectured that the Barker-Larman condition characterizes the ellipsoid. In this work we prove an special case of such conjecture, in particular, we assume that the convex body is centrally symmetric. Our main result is the following: Let be a centrally symmetric and strictly convex body, with center at , and let be a ball in the interior of and not containing : If satisfies the Barker-Larman condition with respect to and is suitable for (intuitively, is suitable for if the boundary of is not very close to the boundary of ), then is an ellipsoid.
Paper Structure (7 sections, 15 theorems, 47 equations, 7 figures)

This paper contains 7 sections, 15 theorems, 47 equations, 7 figures.

Key Result

Theorem 1

Let $K\subset \mathbb{R}^n$, $n\geq3$, be a centrally symmetric and strictly convex body with center at $O$ and let $B\subset \operatorname*{int} K$ be a ball with $O\notin B$. Suppose that $K$ and $B$ are such that: 1) $K$ satisfies the Barker-Larman condition with respect to $B$ and 2) $B$ is suit

Figures (7)

  • Figure 1: The circle $\mathbb{S}^1$ has suitable circle.
  • Figure 2: The chords $a_ib_i$ converge to a common chord of $B$ and $-B$.
  • Figure 3: The shadow boundary $S\partial(K,u)$ is contained in a plane.
  • Figure 4: The line $L_{\Sigma}$ is affine axis of symmetry of $K$.
  • Figure 5: The curve $\delta_{v_0}=\gamma_{v_0}$ is the union of two simple closed con-ti-nuous curves $\gamma_{v_0}^1$, $\gamma_{v_0}^2$.
  • ...and 2 more figures

Theorems & Definitions (33)

  • Theorem 1
  • Theorem 2: Olevjanischnikoff
  • Theorem 3: Rogers
  • Definition 1
  • Remark 1
  • Definition 2
  • Claim 1
  • Remark 2
  • proof
  • Lemma 1
  • ...and 23 more