An injective martingale coupling
David Hobson, Dominykas Norgilas
TL;DR
The paper addresses constructing a strongly injective martingale coupling for any pair of measures $μ,ν$ with $μ leq_{cx} ν$ and $ν$ continuous, ensuring that each target value $y$ is sourced from a unique initial point $x$ in the disintegration. The authors fuse shadow/left-curtain machinery with a careful decomposition into irreducible components and countably many intervals, yielding an explicit, constructive procedure. They develop a robust building block in the regular, atomless setting and extend it to the general continuous case via a sequence of interval-wise injections and patching, establishing the existence of strongly injective couplings and, in the continuous-by-continuous special case, even stronger structural properties (e.g., $ ext{supp}_I( obracket π_x)= ext{supp}( obracket π_x)$ for all $x$). The results enrich the martingale transport literature by providing a concrete, modular construction of injective couplings, clarifying the interplay between convex order, shadow measures, and curtain-couplings, and offering tools potentially relevant for martingale optimal transport and related theories.
Abstract
We give an injective martingale coupling; in particular, given measures $μ$ and $ν$ in convex order on $\mathbb R$ such that $ν$ is continuous, we construct a martingale transport such that for each $y$ in the support of the target law $ν$ there is a {\em unique} $x$ in {a support of} the initial law $μ$ such that (some of) the mass at $x$ is transported to $y$. Then $π$ has disintegration $π(dx,dy) = ν(dy) δ_{θ(y)}(dx)$ for some function $θ$. More precisely we construct a martingale coupling $π$ of the measures $μ$ and $ν$ such that there is a set $Γ_μ$ such that $μ(Γ_μ)=1$ and a disintegration $(π_x)_{x \in Γ_μ}$ of $π$ of the form $π(dx,dy) = π_x(dy) μ(dx)$ such that, with $Γ_{π_x}$ a support of $π_x$, we have $\# \{ x \in Γ_μ: y \in Γ_{π_x} \} \in \{ 0,1 \}$ for all $y$ and $\{ y : \# \{ x \in Γ_μ: y \in Γ_{π_x} \} = 1 \} = supp(ν)$. Moreover, if $μ$ is continuous we may take $Γ_{π_x} = supp(π_x)$ for each $x$. However, we cannot also insist that $Γ_μ= supp (μ)$.
