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Support $τ$-tilting subcategories in exact categories

Jixing Pan, Yaohua Zhang, Bin Zhu

Abstract

Let $\mathcal{E}=(\mathcal{A},\mathcal{S})$ be an exact category with enough projectives $\mathcal{P}$. We introduce the notion of support $τ$-tilting subcategories of $\mathcal{E}$. It is compatible with existing definitions of support $τ$-tilting modules (subcategories) in various context. It is also a generalization of tilting subcategories of exact categories. We show that there is a bijection between support $τ$-tilting subcategories and certain $τ$-cotorsion pairs. Given a support $τ$-tilting subcategory $\mathcal{T}$, we find a subcategory $\mathcal{E}_{\mathcal{T}}$ of $\mathcal{E}$ which is an exact category and $\mathcal{T}$ is a tilting subcategory of $\mathcal{E}_{\mathcal{T}}$. If $\mathcal{E}$ is Krull-Schmidt, we prove the cardinal $|\mathcal{T}|$ is equal to the number of isomorphism classes of indecomposable projectives $Q$ such that ${\rm Hom}_{\mathcal{E}}(Q,\mathcal{T})\neq 0$. We also show a functorial version of Brenner-Butler's theorem.

Support $τ$-tilting subcategories in exact categories

Abstract

Let be an exact category with enough projectives . We introduce the notion of support -tilting subcategories of . It is compatible with existing definitions of support -tilting modules (subcategories) in various context. It is also a generalization of tilting subcategories of exact categories. We show that there is a bijection between support -tilting subcategories and certain -cotorsion pairs. Given a support -tilting subcategory , we find a subcategory of which is an exact category and is a tilting subcategory of . If is Krull-Schmidt, we prove the cardinal is equal to the number of isomorphism classes of indecomposable projectives such that . We also show a functorial version of Brenner-Butler's theorem.
Paper Structure (12 sections, 29 theorems, 63 equations, 2 figures)

This paper contains 12 sections, 29 theorems, 63 equations, 2 figures.

Key Result

Theorem 1.2

(Theorem bijections) Assume $\mathcal{E}$ is weakly idempotent complete. Then there are mutually inverse bijections: Moreover the bijections restrict to bijections

Figures (2)

  • Figure :
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Theorems & Definitions (62)

  • Definition 1.1
  • Theorem 1.2
  • Theorem 1.3
  • Theorem 1.4
  • Lemma 2.1
  • Lemma 2.2
  • Lemma 2.3
  • proof
  • Lemma 2.4
  • Definition 2.5
  • ...and 52 more