On metric approximate subgroups
E. Hrushovski, A. Rodriguez Fanlo
TL;DR
This work extends Hrushovski-style Lie model theory to metric groups by introducing a discretisation-based framework and model-theoretic notions of piecewise hyperdefinable sets. Through discretisation numbers, ultralimits, and compactified definable ideals, the authors construct a Metric Lie Model Theorem asserting that, under doubling-scale control and a constant-growth assumption, the ultraproduct of metric approximate subgroups admits a connected Lie model, with near-subgroup structure and strong commensurability relations to powers of the original set. The paper then derives corollaries that give explicit near-subgroup constructions and doubling-control outcomes, and finally connects these results to de Saxcé’s product theorem, producing product-type dichotomies for simple and semisimple Lie groups in the metric setting. Collectively, these contributions provide a robust structural theory for metric approximate subgroups, linking model theory, discretisation techniques, and Lie group geometry. The results offer a pathway to transfer finite approximate-subgroup structure into the metric regime, with potential applications to growth and regularity phenomena in non-discrete groups.
Abstract
Let $G$ be a group with a metric $\mathrm{d}$ invariant under left and right translations, and let $\bar{\mathbb{D}}_r$ be the ball of radius $r$ around the identity. A $(k,r)$-metric approximate subgroup is a symmetric subset $X$ of $G$ such that the pairwise product set $XX$ is covered by at most $k$ translates of $X\bar{\mathbb{D}}_r$. This notion was introduced in arXiv:math/0601431 along with the version for discrete groups (approximate subgroups). In arXiv:0909.2190, it was shown for the discrete case that, at the asymptotic limit of $X$ finite but large, the "approximateness" (or need for more than one translate) can be attributed to a canonically associated Lie group. Here we prove an analogous result in the metric setting, under a certain finite covering assumption on $X$ replacing finiteness. In particular, if $G$ has bounded exponent, we show that any $(k,r)$-metric approximate subgroup is close to a $(1,r')$-metric approximate subgroup for an appropriate $r'$.
