Table of Contents
Fetching ...

Commensurators of thin normal subgroups and abelian quotients

Thomas Koberda, Mahan Mj

Abstract

We give an affirmative answer to many cases of a question due to Shalom, which asks if the commensurator of a thin subgroup of a Lie group is discrete. In this paper, let $K<Γ<G$ be an infinite normal subgroup of an arithmetic lattice $Γ$ in a rank one simple Lie group $G$, such that the quotient $Q=Γ/K$ is infinite. We show that the commensurator of $K$ in $G$ is discrete, provided that $Q$ admits a surjective homomorphism to $\mathbb{Z}$. In this case, we also show that the commensurator of $K$ contains the normalizer of $K$ with finite index. We thus vastly generalize a result of the authors, which showed that many natural normal subgroups of $\mathrm{PSL}_2(\mathbb{Z})$ have discrete commensurator in $\mathrm{PSL}_2(\mathbb{R})$.

Commensurators of thin normal subgroups and abelian quotients

Abstract

We give an affirmative answer to many cases of a question due to Shalom, which asks if the commensurator of a thin subgroup of a Lie group is discrete. In this paper, let be an infinite normal subgroup of an arithmetic lattice in a rank one simple Lie group , such that the quotient is infinite. We show that the commensurator of in is discrete, provided that admits a surjective homomorphism to . In this case, we also show that the commensurator of contains the normalizer of with finite index. We thus vastly generalize a result of the authors, which showed that many natural normal subgroups of have discrete commensurator in .

Paper Structure

This paper contains 15 sections, 21 theorems, 36 equations.

Key Result

Theorem 1.1

Let $G$ be a semi-simple Lie group with no compact factors and let $\Gamma$ be an irreducible lattice in $G$. Then $\Gamma$ is arithmetic if and only if $\operatorname{Comm}_G(\Gamma)$ is dense in $G$.

Theorems & Definitions (40)

  • Theorem 1.1: Margulis
  • Theorem 1.3
  • Theorem 1.4
  • Lemma 2.1
  • Lemma 2.2
  • Lemma 2.3
  • proof
  • Proposition 2.4
  • Proposition 2.5
  • proof
  • ...and 30 more