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Holography for $\mathcal{N}=1^*$ on $S^4$

Nikolay Bobev, Henriette Elvang, Uri Kol, Timothy Olson, Silviu S. Pufu

Abstract

We construct the five-dimensional supergravity dual of the $\mathcal{N}=1^*$ mass deformation of the $\mathcal{N} =4$ supersymmetric Yang-Mills theory on $S^4$ and use it to calculate the universal contribution to the corresponding $S^4$ free energy at large 't Hooft coupling in the planar limit. The holographic RG flow solutions are smooth and preserve four supercharges. As a novel feature compared to the holographic duals of $\mathcal{N} = 1^*$ on $\mathbb{R}^4$, in our backgrounds the five-dimensional dilaton has a non-trivial profile, and the gaugino condensate is fixed in terms of the mass-deformation parameters. Important aspects of the analysis involve characterizing the ambiguities in the partition function of non-conformal $\mathcal{N}=1$ supersymmetric theories on $S^4$ as well as the action of S-duality on the $\mathcal{N}=1^*$ theory.

Holography for $\mathcal{N}=1^*$ on $S^4$

Abstract

We construct the five-dimensional supergravity dual of the mass deformation of the supersymmetric Yang-Mills theory on and use it to calculate the universal contribution to the corresponding free energy at large 't Hooft coupling in the planar limit. The holographic RG flow solutions are smooth and preserve four supercharges. As a novel feature compared to the holographic duals of on , in our backgrounds the five-dimensional dilaton has a non-trivial profile, and the gaugino condensate is fixed in terms of the mass-deformation parameters. Important aspects of the analysis involve characterizing the ambiguities in the partition function of non-conformal supersymmetric theories on as well as the action of S-duality on the theory.

Paper Structure

This paper contains 31 sections, 164 equations, 4 figures, 1 table.

Figures (4)

  • Figure 1: Plots showing the universal part of the free energy $d^3F/d\mu^3$ as a function of the dimensionless mass $\mu = \pm {\text{i}} ma$ for the one-mass model. The plot on the left (right) shows the results for real (purely imaginary) values of $\mu$. Orange curves are the interpolation function, the black points indicate the data points the interpolation function is based on.
  • Figure 2: The holographic variables $w$ encodes the gaugino condensate $\langle \lambda \lambda \rangle \sim w(\mu) N^2$ with $\mu = \pm {\text{i}} ma$. We find numerically that $w(\mu) = 2\mu^3$; the plots show the results of $w$ vs. $\mu$ for $\mu$ real and purely imaginary. Orange curves are the interpolation function, the black points indicate the data points the interpolation function is based on. The orange curves are indistinguishable from $w(\mu) = 2 \mu^3$ within our precision.
  • Figure 3: Plots showing the universal part of the free energy $d^3F/d\mu^3$ as a function of the dimensionless mass $\mu = \pm {\text{i}} ma$ for the equal-mass model. For $\mu$ real we find solutions with any value, and $d^3F/d\mu^3 \rightarrow \mp 3N^2$ for large $\mu$. When $\mu$ is purely imaginary, we only find solutions with $-2.318 \lesssim {\text{i}}\mu \lesssim 2.318$; as $\mu$ approaches this values, the interpolation function becomes increasingly noisy and does not appear to be reliably determined beyond $|\mu| \gtrsim 2.1$, hence we restrict the plot to this range. Orange curves are the interpolation function, the black points indicate the data points the interpolation function is based on.
  • Figure 4: Scatter plots showing the regions in which we find solutions with smooth IR boundary conditions. On the left, we take real values for $a_0$ and $b_0$. The bounds from (\ref{['IRbnds']}) are the red and blue curves. Note that for real $a_0$ and $b_0$, there is another bound in play too: the region of smooth solutions is bounded by curves that correspond to $s=\pm1$; we do not know an analytic from of these curves in the $b_0,a_0$-plane. The diagonal (purple) are all trivial Euclidean AdS solutions with $\mu=0$. In the plot on the left, the region with $-1< b_0,a_0<-1$ has $-1<s<1$, while the region with $b_0,a_0>1$ has $s<-1$; there is an equivalent region with $b_0,a_0<-1$ in which $s>1$. By the symmetry $(z_i,\tilde{z}_i) \rightarrow (1/z_i,1/\tilde{z}_i)$, the solutions with $-1<a_0,b_0<1$ are equivalent to those with $a_0,b_0 > 1$ or $<-1$.