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Weak local rules for planar octagonal tilings

Nicolas Bédaride, Thomas Fernique

Abstract

We provide an effective characterization of the planar octagonal tilings which admit weak local rules. As a corollary, we show that they are all based on quadratic irrationalities, as conjectured by Thang Le in the 90s.

Weak local rules for planar octagonal tilings

Abstract

We provide an effective characterization of the planar octagonal tilings which admit weak local rules. As a corollary, we show that they are all based on quadratic irrationalities, as conjectured by Thang Le in the 90s.

Paper Structure

This paper contains 7 sections, 11 theorems, 88 equations, 6 figures.

Key Result

Theorem 1

A plane admitting weak local rules is determined by its subperiods.

Figures (6)

  • Figure 1: A celebrated octagonal tiling: the Ammann-Beenker tiling.
  • Figure 2: The window of an Ammann-Beenker tiling, divided into some regions (each of which corresponds to a pattern), with a circled coincidence (left). The slope is slightly changed so that the circled coincidence breaks and a new region appears (right). This corresponds to a new pattern which does not appear in an Ammann-Beenker tiling (compare with Fig. \ref{['fig:ammann_beenker_tiling']}).
  • Figure 3: When an Ammann-Beenker tiling is shifted, it creates lines of flips whose directions are determined by its four subperiods (left). A smaller shift yields a similar picture, but the lines become sparser (right).
  • Figure 4: The irrational slope $(1,\sqrt{2},\sqrt{3},2\sqrt{2},3\sqrt{3},\sqrt{6})$ has one subperiod of type $3$ and one of type $4$. A generic shift thus creates two sets of sparse lines and two sets of sparse flips (left). However, a shift along $\vec{e}_4$ "neutralizes" the lines of flips directed by the subperiod of type $4$ (right).
  • Figure 5: The points in $E_1$ are depicted by squares, while the points in $E_2$ and $E_3$ are respectively depicted by triangles and hexagons. The two lines are at distance at least $3r$ from each other, as well as any two triangles and any two hexagons. The step edge goes between the two lines and stay at distance at least $r/2$ from any point in $E(\vec{s})$, that is, outside the shaded region.
  • ...and 1 more figures

Theorems & Definitions (21)

  • Theorem 1
  • Corollary 1
  • Corollary 2
  • Definition 1: subperiod
  • Definition 2: weak local rules
  • Proposition 1
  • Definition 3: coincidence
  • Proposition 2
  • Proposition 3
  • proof
  • ...and 11 more