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Coefficients and roots of peak polynomials

Sara Billey, Matthew Fahrbach, Alan Talmage

Abstract

Given a permutation $π=π_1π_2\cdots π_n \in \mathfrak{S}_n$, we say an index $i$ is a peak if $π_{i-1} < π_i > π_{i+1}$. Let $P(π)$ denote the set of peaks of $π$. Given any set $S$ of positive integers, define ${\mathcal{P}_S(n)=\{π\in \mathfrak{S}_n:P(π)=S\}}$. Billey-Burdzy-Sagan showed that for all fixed subsets of positive integers $S$ and sufficiently large $n$, $|\mathcal{P}_S(n)|=p_S(n)2^{n-|S|-1}$ for some polynomial $p_S(x)$ depending on $S$. They conjectured that the coefficients of $p_S(x)$ expanded in a binomial coefficient basis centered at $\max(S)$ are all positive. We show that this is a consequence of a stronger conjecture that bounds the modulus of the roots of $p_S(x)$. Furthermore, we give an efficient explicit formula for peak polynomials in the binomial basis centered at $0$, which we use to identify many integer roots of peak polynomials along with certain inequalities and identities.

Coefficients and roots of peak polynomials

Abstract

Given a permutation , we say an index is a peak if . Let denote the set of peaks of . Given any set of positive integers, define . Billey-Burdzy-Sagan showed that for all fixed subsets of positive integers and sufficiently large , for some polynomial depending on . They conjectured that the coefficients of expanded in a binomial coefficient basis centered at are all positive. We show that this is a consequence of a stronger conjecture that bounds the modulus of the roots of . Furthermore, we give an efficient explicit formula for peak polynomials in the binomial basis centered at , which we use to identify many integer roots of peak polynomials along with certain inequalities and identities.

Paper Structure

This paper contains 10 sections, 39 theorems, 63 equations, 4 figures, 1 table.

Key Result

Theorem \oldthetheorem

If $S$ is a nonempty admissible set and $m=\max(S)$, then for $n\geq m$, where $p_S(x)$ is a polynomial of degree $m-1$ depending on $S$ such that $p_S(n)$ is an integer for all integral inputs $n$. If $S=\emptyset$, then $|\mathcal{P}_S(n)|=2^{n-1}$ and $p_\emptyset(n)=1$.

Figures (4)

  • Figure 1: Roots of $p_{\{2,10\}}(z)$.
  • Figure 2: Roots of $p_{\{4,7,15\}}(z)$.
  • Figure 3: Roots of $p_{\{3,5,8,14\}}(z)$.
  • Figure 4: Roots of $p_{\{4,6,9,15\}}(z)$.

Theorems & Definitions (76)

  • Theorem \oldthetheorem: billey
  • Theorem \oldthetheorem
  • Corollary \oldthetheorem
  • Theorem \oldthetheorem
  • Conjecture \oldthetheorem: billey
  • Conjecture \oldthetheorem
  • Lemma \oldthetheorem
  • proof
  • Lemma \oldthetheorem
  • proof
  • ...and 66 more